Answer:
1) 3x² - 15x + 18
2) y-intercept: 18
Zeros: 2 and 3
3) 12x ; (x - 6)²
4) 16x² - 81; (4x - 9)(4x + 9)
Step-by-step explanation:
3x² - 15x + 18
3(x² - 5x + 6)
3[x² - 2x - 3x + 6]
3[x(x - 2) - 3(x - 2)]
3(x - 2)(x - 3)
x - 2 = 0
x = 2
x - 3 = 0
x = 3
Zeros: 2 and 3
y-intercept: at x = 0
3(0-2)(0-3) = 18
x² - 2(x)(b) + 6²
b = 6
2x(6) = 12x
(x - 6)²
16x² - 81
(4x)² - 9²
(4x - 9)(4x + 9)
If both triangles ABE = CBD then <C = <A
Hope it helps.
Answer:
-2
Step-by-step explanation:
x^2 + x=2
Subtract 2 from each side
x^2 + x-2=2-2
x^2 + x-2=0
Factor
What 2 numbers multiply to -2 and add to 1
2*-1 = -2
2+-1 =1
(x-1)(x+2)=0
Using the zero product property
x-1 = 0 x+2 = 0
x=1 x = -2
Product of the roots
1*-2 = -2
If the perimeter of a triangle is 19 cm. The lengths of 3 sides is: a = 8, b = 7, c = 4.
<h3>Parimeter</h3>
Let a = longest
Let b= shortest
Let c= third side
a = 2c
a = (b+ c) - 3
a + 3 = b + c
Using three variables to solve the expression for perimeter
Perimeter= 19 cm
a+ b + c = 19
a + (a + 3) = 19
2a + 3 = 19
2a= 16
Divide both side by 2a
a=16/2
a = 8
a = 2c
8 = 2c
c=8/2
c = 4
a + b + c= 19
8 + b + 4 = 19
12 + b = 19
b=19-12
b = 7
Hence,
a = 8, b = 7, c = 4
Therefore If the perimeter of a triangle is 19 cm. The lengths of 3 sides is: a = 8, b = 7, c = 4.
The complete question is:
Perimeter of triangle is 19cm. If the length of the longest side is twice that of the shortest side and 3 less than the sum of the lengths of the 2 sides find lengths of 3 sides.
Learn more about perimeter here:brainly.com/question/19819849
#SPJ1
Answer:
the answer is quintillion(1e+18)
