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Anastasy [175]
4 years ago
10

PLEASE HELP ASAP

Mathematics
1 answer:
svet-max [94.6K]4 years ago
5 0

Answer:

1) 3x² - 15x + 18

2) y-intercept: 18

Zeros: 2 and 3

3) 12x ; (x - 6)²

4) 16x² - 81; (4x - 9)(4x + 9)

Step-by-step explanation:

3x² - 15x + 18

3(x² - 5x + 6)

3[x² - 2x - 3x + 6]

3[x(x - 2) - 3(x - 2)]

3(x - 2)(x - 3)

x - 2 = 0

x = 2

x - 3 = 0

x = 3

Zeros: 2 and 3

y-intercept: at x = 0

3(0-2)(0-3) = 18

x² - 2(x)(b) + 6²

b = 6

2x(6) = 12x

(x - 6)²

16x² - 81

(4x)² - 9²

(4x - 9)(4x + 9)

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Arlecino [84]

Answer:

4 5/8

Step-by-step explanation:

7 7/8 - 3 1/4

7 7/8 - 3 2/8

4 5/8

8 0
4 years ago
You invest $5000 in an account at 5.5% per year simple interest. How much will you have in the account at the beginning of the 6
NeX [460]

Answer:

The amount in the account in the  beginning of the 6th year is $6375 .

Step-by-step explanation:

Formula

Simple\ interest = \frac{Principle\times Rate\ times Time}{100}

As given

You invest $5000 in an account at 5.5% per year simple interest.

Principle = $ 5000

Rate = 5.5 %

Time = 5 years

(As calculate amount in the account for beginning of 6th year.)

Putting all the values in the formula

Simple\ interest = \frac{5000\times 5.5\times 5}{100}

Simple\ interest = 50\times 5.5\times 5

Simple interest = $ 1375

Amount =  Principle + Simple interest

Putting values in the above formula

Amount =  $5000 + $1375

Amount = $ 6375

Therefore the amount in the account in the  beginning of the 6th year is $ 6375 .

8 0
3 years ago
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Identify the initial value in each formula below, and state whether the formula models exponential growth or
Hitman42 [59]

Answer: Hello mate!

the equation is written is:

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And is hard to work with this, but let's try:

I will interpret this function in two ways:

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second case:

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we know that 2/3 < 1

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5 0
3 years ago
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Neporo4naja [7]
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4 years ago
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