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solong [7]
3 years ago
7

George has a triangle-shaped garden in his backyard. He drew a model of this garden on a coordinate grid with vertices A(4, 2),

B(2, 4), and C(6, 4). He wants to create another, similar-shaped garden, A′B′C′, by dilating triangle ABC by a scale factor of 0.5. What are the coordinates of triangle A′B′C′?
A.
A′(2, 2), B′(1, 2), C′(3, 2)
B.
A′(2, 1), B′(1, 2), C′(3, 2)
C.
A′(8, 4), B′(4, 8), C′(12, 8)
D.
A′(2, 1), B′(1, 2), C′(6, 4)
Mathematics
2 answers:
Nana76 [90]3 years ago
8 0

Answer:

B

Step-by-step explanation:

you divided each cordinate by 2 so (4,2)/2 is (2,1) .

(2,4)/2 = (1,2)

6,2/2 =(3,2)

Otrada [13]3 years ago
3 0

Answer:

b). A' (2,1) , B' (1,2), C' (3,2)

Step-by-step explanation:

Scale factor 0.5 = 1:2

Scale factor = \frac{1}{2} = 0.5

A'= \frac{A}{2} =\frac{(4,2)}{2} =(2,1)\\ B'= \frac{B}{2} =\frac{(2,4)}{2} =(1,2)\\C'= \frac{C}{2} =\frac{(6,4)}{2} =(3,2)\\

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Answer:

a) P(X>np+3\sqrt{np(1-p)}=0.017

b) P(x>1)=0.190

c) P(Y>1)=0.651

Step-by-step explanation:

This a binomial experiment where success is denoted by parts that need rework.

X ∼ B(n, p); n = 20; p = 0.01

The expected value of X is: E(X) = np =20×0.01= 0.2

The variance is: Var(X) = np(1 − p) = 0.2 × 0.99 = 0.198,

The standard deviation SD(X)= \sqrt{0.198} ≈ 0.445

a) P(X>np+3\sqrt{np(1-p)}=P(X>0.2+3×0.445)=P(X>1.535)=P(X≥2)

Probability function is given by:

\frac{n!}{x!(n-x)!} *p^x*(1-p)^{(n-x)}

P(X≥2)=1-P(X<2)=1-P(X=1)-P(X=0)= 1 - \frac{20!}{1!(20-1)!} *(0.01)^{1}*(1-0.01)^{(20-1)}-\frac{20!}{0!(20-0)!} *(0.01)^{0}*(1-0.01)^{(20-0)}

P(X≥2)=1-0.165-0.818=0.017

b) p=0.04

P(x>1)=P(x≥2)= 1 - P(x=1) - P(x=0)= 1 - \frac{20!}{0!(20-1)!} *(0.04)^{1}*(1-0.04)^{(20-1)} - \frac{20!}{0!(20-0)!} *(0.04)^{0}*(1-0.04)^{(20-0)}

P(x>1)= 1 - 0.368 - 0.442=0.190

c) In this case we consider p=0.19 (Probability that X exceeds 1)

In this experiment Y is the number of hours and n= 5 hours.

Then, we check the probability in each hour:

P(Y>1)=1- P(Y=0)

P(Y=0)=\frac{5!}{0!(5-0)!} *(0.19)^{0}*(1-0.19)^{(5-0)}=0.349

P(Y>1)=1-0.349=0.651

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