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Misha Larkins [42]
3 years ago
15

An Olympic-sized swimming pool of uniform depth measures 50 meters by 21 meters. The bottom of the pool is to be treated with a

sealer, and one gallon of the sealer covers 300 square feet of surface. How many gallons of sealer will be required for the job? Round to the nearest whole gallon.
Mathematics
1 answer:
erma4kov [3.2K]3 years ago
8 0

Answer: 4 gallons will be needed.

Step-by-step explanation:

The bottom of the pool is rectangular in shape. The formula for determining the area of a rectangle is expressed as

Area = Length × width

Olympic-sized swimming pool of uniform depth measures 50 meters by 21 meters. The area of the bottom would be

Area = 50 × 21 = 1050 m²

The bottom of the pool is to be treated with a sealer, and one gallon of the sealer covers 300 square feet of surface. This means that the number of gallons of sealer required for the job would be

1050/300 = 3.5gallons Approximately 4 gallons to the nearest gallon

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