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lina2011 [118]
3 years ago
13

The low temperature last month was -5˚F. What is the absolute value of -5?

Mathematics
1 answer:
solong [7]3 years ago
4 0
5

The reason is because |-5| is equal to 5. The absolute value bars make the number positive.
You might be interested in
Find the slope if it exits 2x-5y=6
77julia77 [94]
In standard form, slope is always the negative of the x coefficient over the y coefficient.

If you dont want to have that memorized, you can use algebra to get the equation of the line into slope-intercept form (y=mx+b)

Set it equal to y

2x - 5y = 6
2x = 5y + 6
2x - 6 = 5y
(2/5)x - 6/5 = y
Now it is in slope intercept form. In slope intercept form, the coefficient multiplying with x is the slope of the line. Therefore, the slope equals 2/5.
6 0
3 years ago
Read 2 more answers
(n + 12) x 5 + 7n Need equivalent expression
astraxan [27]

Answer:

12n + 60

General Formulas and Concepts:

<u>Pre-Algebra</u>

Distributive Property

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

(n + 12) × 5 + 7n

<u>Step 2: Simplify</u>

  1. Distribute 5:                     5(n) + 5(12) + 7n
  2. Multiply:                            5n + 60 + 7n
  3. Combine like terms:        12n + 60
6 0
3 years ago
1.Arsenic-74 is used to locate brain tumors. It has a half-life of 17.5 days. 90 mg wereused in a procedure. Write an equation t
Sophie [7]

1)\text{   }N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}

2) 5.625 mg will be left

Explanation:

1) Half-life = 17.5 days

initial amount of Arsenic-74 = 90 mg

To get the equation, we will use the equation of half-life:

\begin{gathered} N_t\text{ = N}_0(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}} \\ where\text{ N}_t\text{ = amount remaining} \\ N_0\text{ = initial amount} \\ t_{\frac{1}{2}\text{ }}\text{ = half-life} \end{gathered}N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}

2) we need to find the remaining amount of Arsenic-74 after 70 days

t = 70

\begin{gathered} N_t=\text{ 90\lparen}\frac{1}{2})^{\frac{70}{17.5}} \\ N_t\text{ = 5.625 mg} \end{gathered}

So after 70 days, 5.625 mg will be left

4 0
1 year ago
PLEASE HELP ME FAST WITH THE CORRECT ANSWER!!!!
Scorpion4ik [409]
Its 144. you just subtract the 121 from 265.
4 0
3 years ago
Which equation has only one solution?
lukranit [14]

Answer:

A, B, and D all only have one solution.

Step-by-step explanation:

7 0
2 years ago
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