Answer:
The sum of 12 terms of AP = -318
Step-by-step explanation:
Points to remember
Sum of n terms of an AP
Sₙ = n/2[ 2a + (n - 1)d]
Where n - number of terms
a - first term
d - common difference
<u>To find the sum of 12 terms</u>
The given AP is 1, -4, -9, -14, . . .
a = 1, d= -5 and n = 12
Sₙ = n/2[ 2a + (n - 1)d]
= 12/2[2*1 + (12 - 1)*(-5)]
= 6[2 + (11*(-5))]
= 6[2 - 55]
= 6 * (-53)
= -318
The sum of 12 terms of AP = -318
Answer:
11.2
Step-by-step explanation:
We can use the pythagorean theorem to find b.
the formula is as follows:
a^2 + b^2 = c^2
We are given a is 10 and c is 15, so we can plug those two numbers in:
10^2 + b^2 = 15^2
Now, we can simplify and solve:
100 + b^2 = 225
b^2 = 125
b = √125
√125 is about 11.1803398875, and to the nearest tenth, this rounds to:
11.2
Answer:
14
Step-by-step explanation:
2(l+b)
2(3+4)
2(7) now do multiply
answer 14m
Answer:
y = -½x + 4
Step-by-step explanation:
1 = -½[6] + b
-3
4 = b
2y + x = 4 →2y = -x + 4 >> y = -½x + 2 [parallel to the above equation]
Parallel lines have SIMILAR <em>RATE</em><em> </em><em>OF</em><em> </em><em>CHANGES</em><em> </em>[<em>SLOPES</em>].
I am joyous to assist you anytime.
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