Answer:
0.59
Step-by-step explanation:
Given that :
Probability of taking bus 1
P(b1) = 90% = 0.9
What is the probability that she will take bus 1 on all five days?
Five days from Monday to friday:
On Monday : p(b1) = 0.9
On Tuesday : p(b1) = 0.9
On Wednesday : p(b1) = 0.9
On Thursday : p(b1) = 0.9
On Friday : p(b1) = 0.9
Here we have an independent event:
Hence, probability of taking bus 1 on all five days :
(0.9 * 0.9 * 0.9 * 0.9 * 0.9)
= 0.59049
= 0.59
