Answer:
C
Step-by-step explanation:
To evaluate f??(- 4) substitute x = - 4 into f(x), that is
f(- 4) = 2(- 4)² + 4(- 4) - 7 = (2 × 16) - 16 - 7 = 32 - 23 = 9 → C
We have:
(30x²+23x+16)/(cx+3) - 13/(cx+3) = 6x+1
(30x²+23x+16 - 13)/(cx+3) = 6x+1
(30x²+23x+3)/(cx+3) = 6x+1
30x²+23x+3 = (cx+3)(6x+1)
30x²+23x+3 = 6cx²+cx+18x+3
30x² + 23x + 3 - 6cx² - cx - 18x - 3 = 0
(30 - 6c)x² +(5 - c)x = 0
6(5 - c)x² +(5 - c)x = 0
(5 - c)(6x² +x) = 0, and x∈ R\ {3/c} ⇒ 5 - c = 0 ⇒ c = 5.
First, find the lowest common multiple of 5 and 8 and it is 40.
So
-32/40 - 35/40
= -67/40
Answer:
the answer is 5 hope this could help
