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SOVA2 [1]
3 years ago
11

How many ways are there to choose a committee of 3 people from a group of 9 people?

Mathematics
1 answer:
QveST [7]3 years ago
3 0
C r = (n!)/(r!(n-r)!)
9 C 3 = (9!)/(3!*(9-3)!)
9 C 3 = (9!)/(3!*6!)
9 C 3 = (9*8*7*6!)/(3!*6!)
9 C 3 = (9*8*7)/(3!)
9 C 3 = (9*8*7)/(3*2*1)
9 C 3 = (504)/(6) 9 C 3 = 84
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hi

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Mashutka [201]
<span>deconstructing
48 : 2 = 24
24 : 2 = 12
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...................................
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8 : 2 = 4
4 : 2 = 2
2 : 2 = 1
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..................................
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6 : 2 = 3
3 : 3 = 1
</span><span>common denominator 48</span>
5 0
3 years ago
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