(6x^2+5x+1)/(3x^2+4x+1)
= (3x+1)(2x+1)/(3x+1)(x+1)
= (2x+1)/(x+1)
Answer:
(2, 8)
Step-by-step explanation:
There are a couple of different ways to do this, but I am going to use substitution since we already have one of those equations solved for y. If y=3x+2, then we can sub 3x+2 in for y in the other equation:
-3x + 2(3x + 2) = 10 and
-3x + 6x + 4 = 10 and
3x + 4 = 10 and
3x = 6 so
x = 2. Now that we know x = 2, we can sub a 2 in for x in either equation to solve for y:
y = 3x + 2 gives us, with the substitution, y = 3(2) + 2 so y = 8. The solution set is (2, 8)
The answer to your question is .792 decimals
P=$17.79-$6.95
P=$10.84
P=$10.84 divide by 0.04
P= 271
Jim ordered 271 prints last month
(4 + 2x)(6 + 2x) =
4(6 + 2x) + 2x(6 + 2x) =
24 + 8x + 12x + 4x^2 =
4x^2 + 20x + 24 <==
