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3 years ago

Help a girl out pls! Lmkkk!

Mathematics

1 answer:

Gre4nikov [31]3 years ago

5 0

I’m not too sure what the question is, please let me know! are you asking what the specific number of the weight of the coffee bean is?

if you divide the weight of the coffee cherry by 20%, you should get the individual weight of the coffee bean!

let me know if this helped, or if you need more help!:)

You might be interested in

g Suppose we have a simple random sample of 400 households drawn from a city with 40,000 households . A 95% confidence interval

kherson [118]

Answer:

gay

Suppose we have a simple random sample of 400 households drawn from a city with 40,000 households . A 95% confidence interval estimate for the population mean number of children per household is [1.1,2.3]. Given this, what is the lower confidence limit for the total number of children in the city

8 0

3 years ago

The overhead reach distances of adult females are normally distributed with a mean of 197.5 cm197.5 cm and a standard deviation

fiasKO [112]

Answer:

a) 5.37% probability that an individual distance is greater than 210.9 cm

b) 75.80% probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

c) Because the underlying distribution is normal. We only have to verify the sample size if the underlying population is not normal.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

$\mu = 197.5, \sigma = 8.3$

a. Find the probability that an individual distance is greater than 210.9 cm

This is 1 subtracted by the pvalue of Z when X = 210.9. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{210.9 - 197.5}{8.3}$

$Z = 1.61$

$Z = 1.61$ has a pvalue of 0.9463.

1 - 0.9463 = 0.0537

5.37% probability that an individual distance is greater than 210.9 cm.

b. Find the probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

Now $n = 15, s = \frac{8.3}{\sqrt{15}} = 2.14$

This probability is 1 subtracted by the pvalue of Z when X = 196. Then

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{196 - 197.5}{2.14}$

$Z = -0.7$

$Z = -0.7$ has a pvalue of 0.2420.

1 - 0.2420 = 0.7580

75.80% probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30?

The underlying distribution(overhead reach distances of adult females) is normal, which means that the sample size requirement(being at least 30) does not apply.

5 0

4 years ago

The value of homes sold in Hampton VA are normally distributed with a mean of $200,000 and a standard deviation of $10,000. If 1

LenKa [72]

Answer:

84%

Step-by-step explanation:

What we must do is calculate the z value for each value and thus find what percentage each represents and the subtraction would be the percentage between those two values.

We have that z is equal to:

z = (x - m) / (sd)

x is the value to evaluate, m the mean, sd the standard deviation

So for 190000 we have:

z = (190000 - 200000) / (10000)

z = -1

and this value represents 0.1587

for 230000 we have:

z = (230000 - 200000) / (10000)

z = 3

and this value represents 0.9987

we subtract:

0.9987 - 0.1587 = 0.84

Which means that it represents 84% of the houses

3 0

3 years ago

I’ll mark brainliest if correct !!!!

Artemon [7]

Answer:

the probability is 1

Step-by-step explanation:

8 0

3 years ago

Jackson has 50 megabytes (MB) of space left on his smartphone. He can download songs that each use 3.5 MB or videos that each us

madreJ [45]

I would just download music tbh

3 0

3 years ago