(
3
x
3
2
y
3
x
2
y
−
1
2
)
−
2
(
3
x
3
2
y
3
x
2
y
-
1
2
)
-
2
Move
x
3
2
x
3
2
to the denominator using the negative exponent rule
b
n
=
1
b
−
n
b
n
=
1
b
-
n
.
⎛
⎝
3
y
3
x
2
y
−
1
2
x
−
3
2
⎞
⎠
−
2
(
3
y
3
x
2
y
-
1
2
x
-
3
2
)
-
2
Multiply
x
2
x
2
by
x
−
3
2
x
-
3
2
by adding the exponents.
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(
3
y
3
x
1
2
y
−
1
2
)
−
2
(
3
y
3
x
1
2
y
-
1
2
)
-
2
Move
y
−
1
2
y
-
1
2
to the numerator using the negative exponent rule
1
b
−
n
=
b
n
1
b
-
n
=
b
n
.
(
3
y
3
y
1
2
x
1
2
)
−
2
(
3
y
3
y
1
2
x
1
2
)
-
2
Multiply
y
3
y
3
by
y
1
2
y
1
2
by adding the exponents.
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⎛
⎝
3
y
7
2
x
1
2
⎞
⎠
−
2
(
3
y
7
2
x
1
2
)
-
2
Change the sign of the exponent by rewriting the base as its reciprocal.
⎛
⎝
x
1
2
3
y
7
2
⎞
⎠
2
(
x
1
2
3
y
7
2
)
2
Use the power rule
(
a
b
)
n
=
a
n
b
n
(
a
b
)
n
=
a
n
b
n
to distribute the exponent.
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(
x
1
2
)
2
3
2
(
y
7
2
)
2
(
x
1
2
)
2
3
2
(
y
7
2
)
2
Simplify the numerator.
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x
3
2
(
y
7
2
)
2
x
3
2
(
y
7
2
)
2
Simplify the denominator.
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x
9
y
7
This is a cube root, so we look for factors of 162 which are perfect cubes.
Find the prime factors of 162:-
162 = 2 * 3 * 3 * 3* 3
27 = 3^3 is a perfect cube
162 = 6 * 27
so ^3√ 162 = ^3√6 * ^3√27 = ^3√6 * 3
so the simplest form is 3 ^3√6
Yeah, x= 7/2 and y= -5/2
Please mark as brainliest and I hope this helps
x > -3
x < 3
<em><u>-3 < x < 3</u></em>
question didn't mention about "x is real number, or positive, or negative etc".. so we can't say anything more
for example: x can be -2,-1,0,1,2
but if only positive, x can be = 1,2
" " negative, x can be = -1, -2
Hope this helps ^-^
Answer:
ill try! <3
Step-by-step explanation:
