Is there a table? Can you attach a picture of it?
It will equal 1/3 4/12= 1/3 1/3 is the answer
b becuces you add the dived
The volume we're looking for is the volume of both cones in the figure.
The volume of a cone is
.
So,
.
<u>Cone 1's variables:</u>
r = 2.6
h = 5
<u>Cone 2's variables:</u>
r = 2.6
h = 3
Now we can just plug and chug!
![V_{tot} = [(3.14)(2.6^2)(\frac{5}{3} )] + [(3.14)(2.6^2)\frac{3}{3} )]\\V_{tot} = [(3.14)(6.76)(1.67)] + [(3.14)(6.76)(1)]\\V_{tot} = (35.45) + (21.23)\\V_{tot} = 56.68](https://tex.z-dn.net/?f=V_%7Btot%7D%20%3D%20%5B%283.14%29%282.6%5E2%29%28%5Cfrac%7B5%7D%7B3%7D%20%29%5D%20%2B%20%5B%283.14%29%282.6%5E2%29%5Cfrac%7B3%7D%7B3%7D%20%29%5D%5C%5CV_%7Btot%7D%20%3D%20%5B%283.14%29%286.76%29%281.67%29%5D%20%2B%20%5B%283.14%29%286.76%29%281%29%5D%5C%5CV_%7Btot%7D%20%3D%20%2835.45%29%20%2B%20%2821.23%29%5C%5CV_%7Btot%7D%20%3D%2056.68)
V = c. 56.6 cubic units