Avagadro's number is just a measurement. One mole is 6.022 X 10^23 of anything - atoms, molecules, marbles... anything.
<span>1) If one mole = 6.022 X 10^23, then 8.00mol of H2S is: </span>
<span>(3.00mol H2S) (6.022 X 10^23 molecules H2S / 1 mol H2S) = 1.8060 X 10^24 molecules H2S. </span>
<span>Rounded to 3 sig figs =1.81 X 10^24 molecules H2S
</span>part2.
<span> This one uses moles in the stoichiometric sense as well as the measurement. One formula unit of MgCl2 contains 1 mole Mg and 2 moles Cl. </span>
<span>First, figure out how many moles of formula units there are. </span>
(1.81 X 10^24 FU's) (1mol MgCl2 / 6.022 X 10^23 FU's) = 3.0056mol MgCl2.
<span>Now, we know that there are 2 moles of Cl in every mole of MgCl2 (2 Cl atoms in every unit of MgCl2). From this we can determine how many moles of Cl atoms there are: </span>
<span>(3.0056mol MgCl2) (2mol Cl atoms / 1mol MgCl2) = 6.0112mol Cl atoms. </span>
<span>Now round to 3 sig figs = 10.0mol Cl atoms</span>
1. ice melting
<span>2. temperature going down at night </span>
<span>3. water evaporating (like a towel drying out) or water drop on the sink </span>
<span>4. dew forming on the mirror after a shower </span>
We have that
The average atomic mass round and to the second decimal place (0.01) is
A_m=126.90
From the question we are told
Find the average atomic mass round and to the second decimal place (0.01)
80% 127I, 17% 126I, 3% 128I
Generally the equation for the Average Mass is mathematically given as
Where
a1 = 127
b1 = 80%
a2 = 126
b2 = 17%
a3 = 128
b3 = 3%
Therefore
In conclusion
The average atomic mass round and to the second decimal place (0.01) is
A_m=126.90
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Thomson's<span> model of the atom did explain some of the electrical properties of the atom due to the electrons, but failed to recognize the positive charges in the atom as particles. In 1911, Ernest Rutherford, a former student of </span>J.J. Thomson, provedThomson's<span> plum pudding structure </span>incorrect<span>.</span>
Answer: 0.58 moles
Explanation: Using ideal gas equation:
PV = nRT
P= pressure =500 kPa=4.93 atm [1 kPa= 0.009atm]
V= volume =3 L
n = no of moles = ?
R= gas constant =0.0821 Latm\molK
T= temperature = 310K