Question

the average adult male can hold about 3 liters of air. how many moles of air can the lung hold at a pressure of 500 kPa and temperature of 310 k

Answer 1

Answer: 0.58 moles

Explanation: Using ideal gas equation:  

PV = nRT

$n=\frac{PV}{TR}$

P= pressure =500 kPa=4.93 atm    [1 kPa= 0.009atm]

V= volume =3 L

n = no of moles = ?

R= gas constant =0.0821 Latm\molK

T= temperature = 310K

$n=\frac{4.93\times 3}{310\times 0.0821}=0.58moles$