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dezoksy [38]
3 years ago
9

It has been discovered that a certain cornfield created in the​ 18th-century was a right triangle. One leg of the triangle was f

ormed by a 210 ft long walking trail. The hypotenuse of the triangle was 90 ft longer than the other leg. What were the dimensions of the​ cornfield?
Physics
1 answer:
Anna007 [38]3 years ago
8 0

Explanation:

Given that,

Let ABC is a triangle such that AB is perpendicular distance, BC is base and AC is the hypotenuse of triangle.

Let AB = 210 ft

AC = 90 + x

BC = x

To find :

The dimensions of the​ cornfield.

Solution :

Pythagoras theorem is used to find the value of x. It is given by :

AB^2+BC^2=AC^2

(210)^2+x^2=(90+x)^2

On solving the above equation we find the value of x, x = 200 ft

So, BC = 200 ft

AC = 90 + 200 = 290 ft

So, the length, base and the hypotenuse of the triangle is 210 ft, 200 ft and 290 ft respectively.

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A proton is accelerated from rest through a potential difference V0 and gains a speed v0. If it were accelerated instead through
Neporo4naja [7]

Answer:

Explanation:

Let the charge on proton be q .

energy gain by proton in a field having potential difference of V₀

= V₀ q

Due to gain of energy , its kinetic energy becomes 1/2 m v₀²

where m is mass and v₀ is velocity of proton

V₀ q = 1/2 m v₀²

In the second case , gain of energy in electrical field

= 2 V₀q , if v be the velocity gained in the second case

2 V₀q = 1/2 m v²

1/2 m v² = 2 V₀q = 2 x 1/2 m v₀²

mv² = 2  m v₀²

v = √2 v₀

6 0
3 years ago
A small child has a wagon with a mass of 10 kilograms. The child pulls on the wagon with a force of 2 newtons. What is the accel
notka56 [123]

Explanation:

F = ma

2 N = (10 kg) a

a = 0.2 m/s²

6 0
3 years ago
PLEASE HELP Due today!
BigorU [14]
So i believe is exercise:)
7 0
3 years ago
What is the resultant of the vecotors shown?
Karolina [17]

D, I believe would be the first minus the second vector.

To solve this I named the first vector as A and the second as B.

So... vector A - B = resultant

or A + (-B)

A negative indicates a direction of a vector so if we flip the direction the other way we have the first vector (A) pointing vertically upwards and then vector B pointing to the west.

Now we have to use the head to tail method, meaning that the head of the first vector has to connect with the tail of the other vector added.

So we should have something like this

(-B)  < -  -  - -  ^

                      |

                      |  (A)

                      |

To add these two vectors, technically A - B, draw a line from the tail of A to the head of -B which would look like image D.

Hope this helped!

3 0
4 years ago
Read 2 more answers
Can anyone explain how to do this to me? It is due tomorrow at 9:30am. Thanks.
Georgia [21]
The 102N acting on the ropes being pulled by eric and kim have some of that force acting horizontally, and some of it vertically. By visualizing it as a right angled triangle, with the hypotenuse the length of the diagonal force, and each side the length of the horizontal and vertical forces, you can use trigonometry to calculate the length of the vertical force. You are told that it is at an angle of 30 with the vertical rope, therefore you know the length of the hypotenuse, and the angle between it and the vertical force, so using trig: (vertical force=x)
x/102=cos(30)
x=102*cos(30)
x=88.33
Therefore the diagonal ropes give a vertical force of 88.33N, and the centre rope, as it acts vertically, gives a vertical force of all 102N. The total:
88.33*2+102=278.66N

I don't know if this is very clear, I hope its good enough to help. If you don't understand, just ask, and I can answer any questions!!! :)
3 0
4 years ago
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