Answer:
cout<<count;
Explanation:
cout<<count;
The above is a C++ command will write to the standard output device (stdout).
That means that one is printing an output on the main output device for that session... whatever that may be (any output device such as monitor, printer, the user's console, a tty session, a file etc).
What that device may be varies depending on how the program is being run and from where.
The kind of statement that writes to standard output are print statement
Answer:
- As an ice cube melts, its shape changes as it acquires the ability to flow. ... A physical change is a change to a sample of matter in which some ... The salt may be regained by boiling off the water, leaving the salt ... The resulting mixture is a solution with a pale green color. ... Answer b: chemical change.
Explanation:
Answer:
(i)The current flow in black wire = 9.67 A (ii) The current low in the red wire is 9.68 A (iii) The current flow in neutral wire is 15.36 A (iv) when 240 volt were disconnected current in black wire is 7.68 A (v) when 240 volt were disconnected current in red wire is 7.68 A (vi) 15.36 A (vii) 6.34 (viii) 9.68 A (ix) 12.02 A
Explanation:
Solution
The current drawn by one amp is
I =P/V
I =200/120
I= 1.67 A
(i) The current flow in the black wire is
IBK = 4 * 1.67 A + 1A + 2A
IBK = 9.67 A
(ii) Current flow in the red wire is
IRD = 3 * 1.67 A + 1.67 A + 1A + 2A
= 8.68A + 1 A = 9.68 A
Note: Kindly find an attached copy of part of the solution to the given question above.
Answer:
4.5sec
Explanation:
From the question above, the following are the parameters that are given
u= 30m/s
v= 50m/s
s= 180m
First of all we have to find the acceleration by using the third equation of motion
V^2= U^2 + 2as
50^2= 30^2 + 2(a)(180)
2500= 900 + 360a
Collect the like terms
2500-900= 360a
1600=360a
Divide both sides by the coefficient of a which is 360
1600/360=360a/360
a= 4.44m/s
The next step is to find the time. To do this we will have to use the first equation of motion
v= u + at
50= 30 + 4.44t
Collect the like terms
50-30= 4.44t
20= 4.44t
Divide both sides by the coefficient of t which is 4.44
20/4.44= 4.44t/4.44
t= 4.5sec
Hence 4.5secs elapses while the auto moves at a distance of 180m
