1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Arte-miy333 [17]
3 years ago
15

Which of the following describes the variable that responds to a change?

Physics
2 answers:
timama [110]3 years ago
8 0
Dependent variable is your answer.
Hitman42 [59]3 years ago
8 0

Answer:

b. Dependent variable

Explanation:

Dependent variable is also referred to as the responding variable.It is what is measured or studied in the experiment. The dependent variable responds to the independent variable. It's what changes as a result of the changes to the independent variable.

You might be interested in
A rocket is fired vertically upwards starting frkm rest. It accelerates at 30m/s for 4secs. At the end of 4secs it runs out of f
HACTEHA [7]

Answer:

t = 16.5 s

Explanation:

First we apply first equation of motion to the accelerated motion of the rocket:

v_{f1} = v_{i1} + at_{1}

where,

vf₁ = final speed of rocket during accelerated motion = ?

vi₁ = initial speed of rocket during accelerated motion  = 0 m/s

a = acceleration of rocket during accelerated motion = 30 m/s²

t₁ = time taken during accelerated motion = 4 s

Therefore,

v_{f} = 0\ m/s + (30\ m/s^2)(4\ s)\\\\v_{f} = 120\ m/s

Now, we analyze the motion rocket when engine turns off. So, the rocket is now in free fall motion. Applying 1st equation of motion:

v_{f2} = v_{i2} + g t_{2}

where,

vf₂ = final speed of rocket after engine is off = 0 m/s

vi₂ = initial speed of rocket after engine is off  = Vf₁ = 120 m/s

g = acceleration of rocket after engine is off = - 9.8  m/s² (negative sign for upward motion)

t₂ = time taken after engine is off = ?

Therefore,

0\ m/s = 120\ m/s + (- 9.8\ m/s^2)(t_{2})\\\\t_{2} = \frac{120\ m/s}{9.8\ m/s^2}\\\\t_{2} = 12.25\ s

So, the time taken from the firing position till the stopping position is:

t = t_{1} + t_{2}\\\\t = 4 s + 12.5 s

<u>t = 16.5 s</u>

8 0
3 years ago
What is first and second conditions of equilibrium?
sdas [7]

I think the answer is the first condition sum of forces acting on a body is zero ( ∑ F =0 ) and the second condition sum of torque acting on a body is ( ∑ τ = 0 )

Could you put me as brainliest?

7 0
3 years ago
Velocity of a car that travled 120 miles in 2 hours
Sophie [7]

60 Miles per hour 60 times 2 is 120

4 0
3 years ago
Read 2 more answers
57. Estimate Potential Energy A boulder with a
Oksanka [162]

Answer: 4.9 x 10^6 joules

Explanation:

Given that:

mass of boulder (m) = 2,500 kg

Height of ledge above canyon floor (h) = 200 m

Gravita-tional potential energy of the boulder (GPE) = ?

Since potential energy is the energy possessed by a body at rest, and it depends on the mass of the object (m), gravitational acceleration (g), and height (h).

GPE = mgh

GPE = 2500kg x 9.8m/s2 x 200m

GPE = 4900000J

Place result in standard form

GPE = 4.9 x 10^6J

Thus, the gravita-tional potential energy of the boulder-Earth system relative to the canyon floor is 4.9 x 10^6 joules

3 0
3 years ago
A cylindrical tank has a tight-fitting piston that allows the volume of the tank to be changed. The tank originally contains air
ValentinkaMS [17]

Answer:

the value of the final pressure is 0.168 atm

Explanation:

Given the data in the question;

Let p₁ be initial pressure, v₁ be initial volume.

After expansion, p₂ is final pressure and v₂ is final volume.

So using the following equations;

p₁v₁ = nRT

p₂v₂ = nRT

hence, p₁v₁ = p₂v₂

we find p₂

p₂ = p₁v₁ / v₂

given that; initial volume v₁ = 0.175 m³, Initial pressure p₁ = 0.350 atm,

final volume v₂ = 0.365 m³

we substitute

p₂ = ( 0.350 atm × 0.175 m³ ) / 0.365 m³

p₂ = 0.06125 atm-m³ / 0.365 m³

p₂ = 0.168 atm

Therefore, the value of the final pressure is 0.168 atm

7 0
3 years ago
Other questions:
  • Which of the following does not use an internal combustion enginea. a cannonb. a lawnmowerc. a windmilld. a car
    12·2 answers
  • The hypothetical situation is described by a physics teacher: two equal mass objects moving at the same speed
    9·1 answer
  • A 133 kg horizontal platform is a uniform disk of radius 1.95 m and can rotate about the vertical axis through its center. A 62.
    10·1 answer
  • After a car accident, the skid marks for one car measured 190 feet. Use the formula s = √ 24 d , where d represents the length o
    8·1 answer
  • In this also please
    6·1 answer
  • A 2.31-kg rope is stretched between supports that are 10.4 m apart, and has a tension in it of 49.2 N. If one end of the rope is
    5·1 answer
  • An object weighs 55.54 newtons. What is its mass if a gravitometer indicates that g = 9.83 m/s2?
    9·1 answer
  • If two people, mass of 70 kg and 85 kg respectively, approach each other with speeds of 4 m/s and 7 m/s, what is the total momen
    14·1 answer
  • Two balls of equal mass collide and stick together as shown in the figure. The initial velocity of ball B is twice that of ball
    8·1 answer
  • A shell is launched with an initial velocity at an angle of 40.0° above horizontal
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!