The feeders in battling machine are represented in proportions and fractions.
- The equation that represents the problem is:
- The feeder can hold <em>30 baseballs</em>, when full
The given parameters are:
<em />
<em> ------ 1/6 full</em>
<em />
<em> --- baseballs added</em>
<em />
<em> ---- 2/3 full</em>
<em />
So, the equation that represents the problem is:
So, we have:
The number of baseballs it can hold is calculated as follows:
Multiply through by 6
Collect like terms
Divide through by 3
Hence, the feeder can hold 30 baseballs, when full
Read more about proportions and fractions at:
brainly.com/question/20337104
Answer:
<em>Hi there!</em>
<u><em>For 1. it should be answer b</em></u>
<u><em>For 2. it would be answer c</em></u>
<u><em>For 3. it is answer a</em></u>
<em>Hope I Helped!</em>
Answer:
X>=1 is the answer
Step-by-step explanation:
then
The graphic is A) or whom is be more or equal to one in the graphic. Right side of the graphic.
Best regards
First it is important to notice that the b is 6, h is 8 and l is? so we find l by using the trigonometry which gives us approximately 13, then we plug it in to V= 1/2 lbh= 1/2 (6)(8)(13)= 312 cm^3
