Answer:
given:
height[h]=8mm
radius [r]=5mm
Now,
Volume of cone=1/3 πr²h=⅓×3.14×5²×8=209mm³
<u>C) 209 </u><u>mm³</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u><u>.</u>
Area of rectangle =lxb =answer
The work is equal to the line integral of
over each line segment.
Parameterize the paths
- from (0, 0, 0) to (2, 0, 0) by
with
, - from (2, 0, 0) to (2, 4, 1) by
with
, - from (2, 4, 1) to (0, 4, 1) by
with
, and - from (0, 4, 1) to (0, 0, 0) by
with 
The work done by
over each segment (call them
) is




Then the total work done by
over the particle's path is 46.
Answer: The volume of the sculpture is 141.84 cubic-feet
Step-by-step explanation: Please see the attachments below
Answer:
The 2 numbers are 32 and 65.
Step-by-step explanation:
x + y = 97 where x and y are the 2 numbers.
x = 2y + 1
Substituting for x in the first equation:
2y + 1 + y = 97
3y = 96
y = 32.
So x = 2y + 1 = 64 + 1 = 65.