Answer:
b= 352/3
or b= 117.33
Step-by-step explanation:
262-3x+85=-5
-3x+(262+85)=-5
simplify the arithmetic
-3x+347=-5
Group all constants on the right side of the equation
-3x+347=-5
Subtract from both sides:
-3x+347-347=-5-347
Simplify the arithmetic:
-3x=-5-347
-3x=-352
isolate the x
-3x=-352
Divide both sides by -3
-3x/-3}=-352/-3}
Cancel out the negatives
3x/3}=-352/-3
Simplify the fraction
x= -352/-3
Cancel out the negatives
x=352/3
∑ Hey, petalssquad10 ⊃
Answer:
( 10 x + 10 ) = 110
Step-by-step explanation:
As you can see this following diagram shown a vertical angles which are angles that are opposite of each other when two lines cross. You can also see it kind of look like a "x". Vertical angles also means that they have the same angle measure. A example is if this angle is "110" then the other sides equal to "110''.
Hence, the equation we can be used to solve for x in the following diagram is:
( 10 x + 10 ) = 110
You can also refer to the image below:
<u><em>xcookiex12</em></u>
<u><em></em></u>
<em>8/18/2022</em>
Put 163 on top and then 66 on bottoms of the equation and then subtract. 3-6 u can't do so u barrow from the 6 and turn the 6 into a 5 and the 3 into a 13 then subtract 13 from 6 and get 7 then u can't subtract 5 from 6 so barrow from the 1 to make the 5 a 15 and the 1 to a 0 and then subtract 15 from 6 and get 9 and ur answer is 97!
Answer:
The<em> p</em>-value of the test is 0.1212.
Step-by-step explanation:
A one sample <em>z</em>-test can be performed to determine whether the mean hourly wage differs from the reported mean of $24.57 for the goods-producing industries.
The hypothesis is defined as:
<em>H₀</em>: The mean hourly wage is same as the reported mean of $24.57 for the goods-producing industries, i.e. <em>μ</em> = $24.57.
<em>Hₐ</em>: The mean hourly wage differs from the reported mean of $24.57 for the goods-producing industries, i.e. <em>μ</em> ≠ $24.57.
The information provided is:

Compute the test statistic as follows:

The test statistic value is, <em>z</em> = -1.55.
Compute the <em>p</em>-value of the test as follows:

*Use a <em>z</em>-table for the probability.
Thus, the<em> p</em>-value of the test is 0.1212.