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egoroff_w [7]
3 years ago
11

Scott has a bag with 144 pieces of candy in it. He gives his sister 25% of the candy. How many pieces of candy does Scott give h

is sister?
Mathematics
2 answers:
morpeh [17]3 years ago
7 0

Answer:

Scott gives his sister 36 peices of candy

Step-by-step explanation:

Andrej [43]3 years ago
4 0

Answer:

Step-by-step explanation:

Scott has 144 pieces of candy

25% is one 4th

144/4=36

he gives to his sister 36

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35+70=35(1+2) yes or no​
nordsb [41]

Answer:

Yes.

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
find a curve that passes through the point (1,-2 ) and has an arc length on the interval 2 6 given by 1 144 x^-6
taurus [48]

Answer:

f(x) = \frac{6}{x^2} -8 or f(x) = -\frac{6}{x^2} + 4

Step-by-step explanation:

Given

(x,y) = (1,-2) --- Point

\int\limits^6_2 {(1 + 144x^{-6})} \, dx

The arc length of a function on interval [a,b]:  \int\limits^b_a {(1 + f'(x^2))} \, dx

By comparison:

f'(x)^2 = 144x^{-6}

f'(x)^2 = \frac{144}{x^6}

Take square root of both sides

f'(x) =\± \sqrt{\frac{144}{x^6}}

f'(x) = \±\frac{12}{x^3}

Split:

f'(x) = \frac{12}{x^3} or f'(x) = -\frac{12}{x^3}

To solve fo f(x), we make use of:

f(x) = \int {f'(x) } \, dx

For: f'(x) = \frac{12}{x^3}

f(x) = \int {\frac{12}{x^3} } \, dx

Integrate:

f(x) = \frac{12}{2x^2} + c

f(x) = \frac{6}{x^2} + c

We understand that it passes through (x,y) = (1,-2).

So, we have:

-2 = \frac{6}{1^2} + c

-2 = \frac{6}{1} + c

-2 = 6 + c

Make c the subject

c = -2-6

c = -8

f(x) = \frac{6}{x^2} + c becomes

f(x) = \frac{6}{x^2} -8

For: f'(x) = -\frac{12}{x^3}

f(x) = \int {-\frac{12}{x^3} } \, dx

Integrate:

f(x) = -\frac{12}{2x^2} + c

f(x) = -\frac{6}{x^2} + c

We understand that it passes through (x,y) = (1,-2).

So, we have:

-2 = -\frac{6}{1^2} + c

-2 = -\frac{6}{1} + c

-2 = -6 + c

Make c the subject

c = -2+6

c = 4

f(x) = -\frac{6}{x^2} + c becomes

f(x) = -\frac{6}{x^2} + 4

3 0
3 years ago
Cedarburg's zoo has two elephants. The male elephant weighs 3 3/4 tons and the female
kati45 [8]

Answer:

the male weigh than the female

Step-by-step explanation:

\frac{19}{6}=3\frac{1}{6}

3 0
3 years ago
State the three pairs of equal parts in ∆ABC and ∆DAB .write the result in symbolic form:is AD=BC why
Aliun [14]

Answer:

\textcolor{red}{(i) ΔABC ≈ ΔPQR(ii) ΔDEF ≈ ΔNML(iii) Not congruent(iv) ΔADB ≈ ΔADC} \\ \textcolor

7 0
4 years ago
Evaluate the expression for x = 5, y = 3, and z = 14 . <br><br> 5x−6y+20z4yz
anzhelika [568]

Answer: 47040

Step-by-step explanation:

5x5-6x3+20x14x4x3x14

25-18+47040

47033

7 0
3 years ago
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