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Olegator [25]
4 years ago
13

Solve the proportion.

Mathematics
2 answers:
hjlf4 years ago
5 0
16(156.25)=50X
2,500=50X
X=50
Delicious77 [7]4 years ago
4 0
16x 152.25=50(x)
2436=50x
X=48.72
You might be interested in
3 (4x - 2) - 5x = 6 - 7 (-x -2)
Alona [7]

Answer:

0=26

Step-by-step explanation:

Distribute

3(4−2)−5=6−7(−−2)

12−6−5=6-7(-x−2)

Combine like terms

12−6−5=6−7(−−2)

7−6=6−7(−−2)

Distribute

7−6=6−7(−−2)

7−6=6+7x+14

Answer

0=26

4 0
3 years ago
Of the customers who enter a store for stereo speakers, only 24% make purchases. if 38 customers enter the showroom tomorrow, fi
notsponge [240]
24% of 38 = (1 - 24/100) × 38 = 28,88 = 29

24 % ←→ 29
x% ←→ 10

x = 10 × 24 ÷ 29
x = 8,27586
x = 8 %

ANSWER 8%
6 0
3 years ago
I’ve been stuck on this question for awhile and i can’t answer it
vfiekz [6]

Answer:

PEMDAS.

parenthesis first, then exponents, next would be mutiplication/division, then lastple add/subtract.

Step-by-step explanation:

first would be 15-7, then the 3^2, etc

8 0
3 years ago
3.30 Survey response rate. Pew Research reported in 2012 that the typical response rate to their surveys is only 9%. If for a pa
Artist 52 [7]

Answer:

0% probability that at least 1,500 will agree to respond

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 15000, p = 0.09

So

\mu = E(X) = np = 15000*0.09 = 1350

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{15000*0.09*0.91} = 35.05

What is the probability that at least 1,500 will agree to respond

This is 1 subtracted by the pvalue of Z when X = 1500-1 = 1499. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1499 - 1350}{35.05}

Z = 4.25

Z = 4.25 has a pvalue of 1.

1 - 1 = 0

0% probability that at least 1,500 will agree to respond

6 0
4 years ago
Andy is bying a car he negotiated a 7% decrease on a £ 6 500 car he will pay a full balance over 12 equal month payments calcula
Scrat [10]
I don’t know the answer, but when you get it can you tell me I have a similar problem on my test
8 0
3 years ago
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