What is the formula to find the hight of a triangle?

What is the volume of this triangular prism? A triangular prism. The triangular base has a base of 28 centimeters and height of

mamaluj [8]

Answer:

The volume of the triangular prism is 5676.16 cm³

Step-by-step explanation:

The area of the triangular base A = bh/2 where b = base = 28 cm and h = height = 22.4 cm.

Now, the volume of the triangular prism, V = area of triangular base, A × height of prism, h'

V = Ah' where h = height of prism = 18.1 cm

So, V = bhh'/2

Substituting the values of the variables into the equation for V, we have

V = bhh'/2

V = 28 cm × 22.4 cm × 18.1 cm/2

V = 14 cm × 22.4 cm × 18.1 cm

V = 5676.16 cm³

So, the volume of the triangular prism is 5676.16 cm³

3 0

3 years ago

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Hey:) can you please help me posted picture of question

elixir [45]

Option B gives the correct answer.

The step by step solution using the FOIL method of multiplication is given below:

$(8 x^{5}+9)(8 x^{3}+9) \\ \\ 
 =8 x^{5} (8 x^{3}+9) +9(8 x^{3}+9) \\ \\ 
=64 x^{8} +72 x^{5}+72 x^{3}+81$

3 0

3 years ago

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Casey divided a 3 1/5 pound bag of pears among his eight friends how many pound of pears did each friend receive

Troyanec [42]

2/5

because if you turn 3 1/5 into an improper fraction that 16/5 divided by 8/1 equals 16/40 which when simplified equals 2/5

3 0

4 years ago

Looking at the top of tower A and base of tower B from points C and D, we find that ∠ACD = 60°, ∠ADC = 75° and ∠ADB = 30°. Let t

katrin2010 [14]

Answer:

$\text{Exact: }AB=25\sqrt{6},\\\text{Rounded: }AB\approx 61.24$

Step-by-step explanation:

We can use the Law of Sines to find segment AD, which happens to be a leg of $\triangle ACD$ and the hypotenuse of $\triangle ADB$ .

The Law of Sines states that the ratio of any angle of a triangle and its opposite side is maintained through the triangle:

$\frac{a}{\sin \alpha}=\frac{b}{\sin \beta}=\frac{c}{\sin \gamma}$

Since we're given the length of CD, we want to find the measure of the angle opposite to CD, which is $\angle CAD$ . The sum of the interior angles in a triangle is equal to 180 degrees. Thus, we have:

$\angle CAD+\angle ACD+\angle CDA=180^{\circ},\\\angle CAD+60^{\circ}+75^{\circ}=180^{\circ},\\\angle CAD=180^{\circ}-75^{\circ}-60^{\circ},\\\angle CAD=45^{\circ}$

Now use this value in the Law of Sines to find AD:

$\frac{AD}{\sin 60^{\circ}}=\frac{100}{\sin 45^{\circ}},\\\\AD=\sin 60^{\circ}\cdot \frac{100}{\sin 45^{\circ}}$

Recall that $\sin 45^{\circ}=\frac{\sqrt{2}}{2}$ and $\sin 60^{\circ}=\frac{\sqrt{3}}{2}$ :

$AD=\frac{\frac{\sqrt{3}}{2}\cdot 100}{\frac{\sqrt{2}}{2}},\\\\AD=\frac{50\sqrt{3}}{\frac{\sqrt{2}}{2}},\\\\AD=50\sqrt{3}\cdot \frac{2}{\sqrt{2}},\\\\AD=\frac{100\sqrt{3}}{\sqrt{2}}\cdot\frac{ \sqrt{2}}{\sqrt{2}}=\frac{100\sqrt{6}}{2}={50\sqrt{6}}$

Now that we have the length of AD, we can find the length of AB. The right triangle $\triangle ADB$ is a 30-60-90 triangle. In all 30-60-90 triangles, the side lengths are in the ratio $x:x\sqrt{3}:2x$ , where $x$ is the side opposite to the 30 degree angle and $2x$ is the length of the hypotenuse.

Since AD is the hypotenuse, it must represent $2x$ in this ratio and since AB is the side opposite to the 30 degree angle, it must represent $x$ in this ratio (Derive from basic trig for a right triangle and $\sin 30^{\circ}=\frac{1}{2}$ ).