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STatiana [176]
3 years ago
6

Keitaro walks at a pace of 3 miles per hour and runs at a pace of 6 miles per hour. Each month, he wants to complete at least 36

miles but not more than 90 miles. The system of inequalities represents the number of hours he can walk, w, and the number of hours he can run, r, to reach his goal. 3w + 6r ≥ 36 3w + 6r ≤ 90 Which combination of hours can Keitaro walk and run in a month to reach his goal?

Mathematics
2 answers:
ipn [44]3 years ago
4 0
Idk but when I solved it out I got 120 >_  2160 <_  90
bonufazy [111]3 years ago
4 0

Answer:

<h2>2 hours walking and 12 hours running</h2>

Step-by-step explanation:

The choice to this question are

  • 2 hours walking; 12 hours running
  • 4 hours walking; 3 hours running
  • 9 hours walking; 12 hours running
  • 12 hours walking; 10 hours running

The given inequalities are

3w+6r\geq 36

3w+6r\leq 90

Where w is walk and r is run.

First, we need to graph this system. The image attached shows both inequalities and the area of solution, where x=w and y=r.

In other words, any  point in side the intesection of shaded areas is part of the solution to this problem.

So, 2 hours walking and 12 hours running is inside the area of solution, because represents point (2,12).

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Answer:

13 and 53

Step-by-step explanation:

First Integer: x

Larger integer: 5x-12

66=x+(5x-12)

66= x+5x-12

66=6x+12

78=6x

13=x

First Integer: 13

Larger Integer: 13*5-12= 65-12=53

Check Work:

13+53=66

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