Keitaro walks at a pace of 3 miles per hour and runs at a pace of 6 miles per hour. Each month, he wants to complete at least 36
miles but not more than 90 miles. The system of inequalities represents the number of hours he can walk, w, and the number of hours he can run, r, to reach his goal. 3w + 6r ≥ 36 3w + 6r ≤ 90 Which combination of hours can Keitaro walk and run in a month to reach his goal?
2 answers:
Answer:
<h2>2 hours walking and 12 hours running</h2>Step-by-step explanation:
The choice to this question are
- 2 hours walking; 12 hours running
- 4 hours walking; 3 hours running
- 9 hours walking; 12 hours running
- 12 hours walking; 10 hours running
The given inequalities are
Where is walk and
is run.
First, we need to graph this system. The image attached shows both inequalities and the area of solution, where and
.
In other words, any point in side the intesection of shaded areas is part of the solution to this problem.
So, 2 hours walking and 12 hours running is inside the area of solution, because represents point (2,12).
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Well, you have to be given an interval. That is not an interval.
You should be given something like
If you add those fractions up you'll just get a point on the number line.
Find the LCD for all of them which is 9/6 - 4/6 + 3/6 = 8/6 = 2/3
You'll end up with a point on 2/3
You should be given something like
If you add those fractions up you'll just get a point on the number line.
Find the LCD for all of them which is 9/6 - 4/6 + 3/6 = 8/6 = 2/3
You'll end up with a point on 2/3