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Katyanochek1 [597]
2 years ago
12

Fiona drew a regular polygon that first maps directly onto itself after rotating 15 degrees. How many sides does the polygon hav

e?
Mathematics
1 answer:
monitta2 years ago
4 0
The answer is the polygon have 24 sides.

Solution is shown step by step: Let c be the 15 degrees.

1. C = 360 divided by n

2. 15 = 360 divided by n

3. then transpose n to the other side
    15n = 360

4. divide both sides by 15
    n = 360 divided by 15

5. n = 24
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Carran is building a fence around his rectangular yard. The fence will cover the front and the 2 sides of the yard. The
dolphi86 [110]

9514 1404 393

Answer:

  • sides: 12 feet
  • front: 28 feet

Step-by-step explanation:

Let x represent the length of one side of the yard. Then the width of the yard is 2x+4, and the perimeter is ...

  P = 2(L +W) . . . . . . . . . . formula for perimeter of a rectangle

  80 = 2(x + (2x+4)) . . . . . with values from the problem filled in

  40 = 3x +4 . . . . . . . . divide by 2, collect terms

  36 = 3x . . . . . . . . . subtract 4

  12 = x . . . . . . . . . divide by 3. This is the length of the side fence.

  2x +4 = 2(12) +4 = 28

The fence is 12 feet on the sides and 28 feet on the front. (Its total length is 52 feet.)

7 0
2 years ago
Please help me on these please it’s due today
Nezavi [6.7K]

Answer:

I don't know

Step-by-step explanation:

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4 0
2 years ago
This is algebra 10 please help :(
KengaRu [80]
I believe the answer is 3
3 0
3 years ago
Which of the equations below could be the equation of this parabola?
nirvana33 [79]

Answer:

 y=-4x^2  is the equation of this parabola.

Step-by-step explanation:

Let us consider the equation

y=-4x^2

\mathrm{Domain\:of\:}\:-4x^2\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

\mathrm{Range\:of\:}-4x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\le \:0\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:0]\end{bmatrix}

\mathrm{Axis\:interception\:points\:of}\:-4x^2:\quad \mathrm{X\:Intercepts}:\:\left(0,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:0\right)

As

\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=a\left(x-m\right)\left(x-n\right)

\mathrm{is\:the\:average\:of\:the\:zeros}\:x_v=\frac{m+n}{2}

y=-4x^2

\mathrm{The\:parabola\:params\:are:}

a=-4,\:m=0,\:n=0

x_v=\frac{m+n}{2}

x_v=\frac{0+0}{2}

x_v=0

\mathrm{Plug\:in}\:\:x_v=0\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}

y_v=-4\cdot \:0^2

y_v=0

Therefore, the parabola vertex is

\left(0,\:0\right)

\mathrm{If}\:a

\mathrm{If}\:a>0,\:\mathrm{then\:the\:vertex\:is\:a\:minimum\:value}

a=-4

\mathrm{Maximum}\space\left(0,\:0\right)

so,

\mathrm{Vertex\:of}\:-4x^2:\quad \mathrm{Maximum}\space\left(0,\:0\right)

Therefore,  y=-4x^2  is the equation of this parabola. The graph is also attached.

7 0
3 years ago
7)PLEASE HELP WITH QUESTION. MARKING BRAINLIEST + POINTS.
yanalaym [24]
No triangle is formed

7 0
3 years ago
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