Ava worked 40 hours this week and made $520. How much did he earn each hour?

If each customer takes 3 minutes to check out, what is the probability that it will take more than 9 minutes for all the custome

AnnyKZ [126]

Using a discrete probability distribution, it is found that there is a 0.15 = 15% probability that it will take more than 9 minutes for all the customers currently in line to check out.

<h3>What is the discrete probability distribution?</h3>

Researching the problem on the internet, it is found that the distribution for the number of customers in line at the store is given by:

P(X = 0) = 0.2;

P(X = 1) = 0.15;

P(X = 2) = 0.30;

P(X = 3) = 0.20;

P(X = 4) = 0.10;

P(X = 5) = 0.05;

Hence, since each customer takes 3 minutes to check out, the probability that it will take more than 9 minutes for all the customers currently in line to check out is the probability that there are more than 3 customers, hence:

P(X > 3) = P(X = 4) + P(X = 5) = 0.10 + 0.05 = 0.15.

0.15 = 15% probability that it will take more than 9 minutes for all the customers currently in line to check out.

More can be learned about a discrete probability distribution at brainly.com/question/24855677

7 0

1 year ago

De acuerdo con la tercera ley de movimiento planetario de Kepler, la masa de un planeta es directamente proporcional al cubo de

Sunny_sXe [5.5K]

Answer:

La masa del Sol es $2.509\times 10^{31}$ kilogramos.

Step-by-step explanation:

Tras una lectura cuidadosa al enunciado, tenemos que la Tercera Ley de Kepler queda descrita por la siguiente relación:

$M \propto \frac{r^{3}}{T^{2}}$

$M = k\cdot \frac{r^{3}}{T^{2}}$ (Eq. 1)

Donde:

$r$ - Distancia entre los centros del planeta y el satélite, medido en kilómetros.

$T$ - Período oribital del satélite, medido en días.

$k$ - Constante de proporcionalidad, medida en kilogramo-días cuadrados por kilómetro cúbico.

$M$ - Masa del planeta, medida en kilogramos.

Podemos obtener la masa del Sol mediante la siguiente relación:

$\frac{M_{S}}{M_{E}} = \frac{\frac{r_{E}^{3}}{T_{E}^{2}} }{\frac{r_{M}^{3}}{T_{M}^{2}} }$

$\frac{M_{S}}{M_{E}} = \left(\frac{T_{M}}{T_{E}} \right)^{2}\cdot \left(\frac{r_{E}}{r_{M}} \right)^{3}$ (Eq. 2)

Donde:

$T_{M}$ , $T_{E}$ - Períodos orbitales de la Luna y la Tierra, medidos en días.

$r_{E}$ , $r_{M}$ - Distancias entre la Tierra y el Sol, así como entre la Luna y la Tierra, medidas en kilómetros.

$M_{S}$ , $M_{E}$ - Masas del Sol y la Tierra, medidos en kilogramos.

Si $M_{E} = 75.97\times 10^{24}\,kg$ , $T_{E} = 365.3\,d$ , $T_{M} = 27.3\,d$ , $r_{M} = 3.84\times 10^{5}\,km$ y $r_{E} = 1.496\times 10^{8}\,km$ , entonces tenemos que la masa del Sol es:

$M_{S} = \left(\frac{T_{M}}{T_{E}} \right)^{2}\cdot \left(\frac{r_{E}}{r_{M}} \right)^{3}\cdot M_{E}$

$M_{S} = \left(\frac{27.3\,d}{365.3\,d} \right)^{2}\cdot \left(\frac{1.496\times 10^{8}\,km}{3.84\times 10^{5}\,km} \right)^{3}\cdot (75.97\times 10^{24}\,kg)$

$M_{S} = 2.509\times 10^{31}\,kg$

La masa del Sol es $2.509\times 10^{31}$ kilogramos.

7 0

3 years ago

Solve

Deffense [45]

Answer:

The formula for calculating mean is summation x/n

There fore

5

-7

3

2

-6

-4

8

-2

1

The answer is -4 which A

4

7 0

2 years ago

Summative practice

UkoKoshka [18]

Answer:

the answer is written in the picture.

3 0

3 years ago

Please help, will mark brainliest if correct!!!

Hatshy [7]

Answer:8.5

Step-by-step explanation:

Pythagorean Theorem

A

a^2 + b^2 = c^2

3^2 + 8^2 = c^2

9 + 64 = c^2

73 = c^2

C= Sqrt (73)

C = 8.5

6 0

3 years ago