![\dfrac\partial{\partial y}\left[e^{2y}-y\cos xy\right]=2e^{2y}-\cos xy+xy\sin xy](https://tex.z-dn.net/?f=%5Cdfrac%5Cpartial%7B%5Cpartial%20y%7D%5Cleft%5Be%5E%7B2y%7D-y%5Ccos%20xy%5Cright%5D%3D2e%5E%7B2y%7D-%5Ccos%20xy%2Bxy%5Csin%20xy)
![\dfrac\partial{\partial x}\left[2xe^{2y}-y\cos xy+2y\right]=2e^{2y}+y\sin xy](https://tex.z-dn.net/?f=%5Cdfrac%5Cpartial%7B%5Cpartial%20x%7D%5Cleft%5B2xe%5E%7B2y%7D-y%5Ccos%20xy%2B2y%5Cright%5D%3D2e%5E%7B2y%7D%2By%5Csin%20xy)
The partial derivatives are not equal, so the equation is not exact.
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9514 1404 393
Answer:
68 4/7 miles/hour
Step-by-step explanation:
The unit rate is found by dividing miles by hours:
(120 miles)/(7/4 hours) = 480/7 miles/hour = 68 4/7 miles/hour
Answer:
Well i think so
Step-by-step explanation:
its just an equal sign on different sides
Answer:
(x, y) → (–x, –y)
Step-by-step explanation:
The rule for 180° rotation about the origin is

The coordinates of the image are obtained by negating both the x and y coordinates of the preimage.
Whether the rotation is clockwise or counterclockwise, the rule remains the same.
The correct option is (x, y) → (–x, –y)