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Anvisha [2.4K]
2 years ago
12

Compare the graph of g(x)=−3x2 to the graph of f(x)=x2

Mathematics
1 answer:
aev [14]2 years ago
3 0

Answer:

There was a reflection about the x-axis and a vertical stretch.

Step-by-step explanation:

This is a hyperbola.

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belka [17]
Just doing this to get points... :(
5 0
2 years ago
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Let f(x)=3(12)x+1. Which is equal to f(1)?
aalyn [17]

Answer:

just substitute the value of x as 1

f(x)=3(12)x+1

f(1)=3(12)(1)+1

f(1)=3(12)(1)+1

f(1)=36+1

f(1)=37

5 0
3 years ago
Q=p(r+s) solve for p
pav-90 [236]
Q = p(r+s)
--------------
(r+s) (r+s) Divide both sides by (r+s) so you can get the p bu itself this way you get q / (r+s) = p
4 0
3 years ago
Need to write steps and solve <br> thanks
nalin [4]

<u>Answer:</u>

The coordinates of endpoint V is (7,-27)

<u>Solution:</u>

Given that the midpoint of line segment UV is (5,-11) And U is (3,5).

To find the coordinates of V.

The formula for mid-point of a line segment is as follows,

Midpoint of UV is \frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}

As per the formula,  \frac{x_{1}+x_{2}}{2}=5, \frac{y_{1}+y_{2}}{2}=-11

Here x_{1}=3; y_{1}=5

Substituting the value of x_{1} we get,

\frac{3+x_{2}}{2}=5

3+x_{2}=5\times2

x_{2}=10-3

x_{2}=7

Substituting the value of x_{2} we get,

\frac{5+y_{2}}{2}=-11

5+y_{2}=-11\times2

y_{2}=-22-5

y_{2}=-27

So, the coordinates of V is (7,-27)

7 0
3 years ago
Find the value of z in the isosceles triangle shown below.<br> V20<br> V20<br> 8
Andrews [41]

Answer:

<h3>x = 2</h3>

Step-by-step explanation:

use Pythagorean theorem:

a² + b² = c²

where a = x

           b = 8/2 = 4  

           c = √20

plugin values into the formula:

x² + 4² = (√20)²

x² + 16 = 20

x² = 20 - 16

x = √4

x = 2

5 0
2 years ago
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