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Vaselesa [24]
3 years ago
13

See attached image. Thanks!

Mathematics
1 answer:
madam [21]3 years ago
6 0

Answer:

17

Step-by-step explanation:

n(Band and Choir only)

= 25 - 11 - 7 - 3 = 4

n(Math and Band only)

= 7

n(Math and Choir only)

= 57 - (25 + 17 + 9)

= 6

Exactly 2:

4 + 7 + 6

= 17

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Which is the slope of the line that passes through the points (-5,6) and (-3,2)?
vitfil [10]

The slope of the line passes through the points (-5,6) and (-3,2) is 2.

<h3>What is a slope?</h3>

Slope or the gradient is the number or the ratio which determines the direction or the steepness of the line. The slope is also defined as the ratio of the rise to the run.

Given that the line that passes through the points (-5,6) and (-3,2).

The slope of the line is calculated by the formula,

Slope = ( y₂ - y₁ ) / ( x₂ - x₁ )

Slope = ( 6 - 2) / ( -3 + 5)

Slope = 4 / 2

Slope = 2

Therefore, the slope of the line passes through the points (-5,6) and (-3,2) is 2.

To know more about slopes follow

brainly.com/question/3493733

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7 0
1 year ago
Type the correct answer in each box. A circle is centered at the point (5, -4) and passes through the point (-3, 2). The equatio
Galina-37 [17]

Answer:

(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}

Step-by-step explanation:

Given:

Center of circle is at (5, -4).

A point on the circle is (x_1,y_1)=(-3, 2)

Equation of a circle with center (h,k) and radius 'r' is given as:

(x-h)^2+(y-k)^2=r^2

Here, (h,k)=(5,-4)

Radius of a circle is equal to the distance of point on the circle from the center of the circle and is given using the distance formula for square of the distance as:

r^2=(h-x_1)^2+(k-y_1)^2

Using distance formula for the points (5, -4) and (-3, 2), we get

r^2=(5-(-3))^2+(-4-2)^2\\r^2=(5+3)^2+(-6)^2\\r^2=8^2+6^2\\r^2=64+36=100

Therefore, the equation of the circle is:

(x-5)^2+(y-(-4))^2=100\\(x-5)^2+(y+4)^2=100

Now, rewriting it in the form asked in the question, we get

(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}

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3 years ago
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How do I answer this question?
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Yes because you use the distributive property
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