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anzhelika [568]
3 years ago
7

Help,anyone can help me do quetion,I will mark brainlest.​

Mathematics
2 answers:
Nesterboy [21]3 years ago
8 0
A. 2
B1+b2/2 •h= A 10+x/2 •8= 48
B. 4

B1+b2/2 •h= A 2+7/2 •x= 18

Hope this helps!!
Serhud [2]3 years ago
5 0

Answer:

a)    x = 2

b)    x = 4

Step-by-step explanation:

a = (b₁ + b₂)/2 * h

----------------------------

a)

48 = (10 + x)/2 * 8

Divide both sides by 8

6 = (10 + x)/2

multiply both sides by 2

12 = 10 + x

Subtract 10 from both sides

2 = x

x = 2

---------------------------------

b)

18 = (7 + 2)/2 * x

18 = 4.5 * x

divide both sides by 4.5

4 = x

x = 4

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a rectangles perimeter and area have the same numerical value. the width of the rectangle is 9 units . what is the length of the
attashe74 [19]

Answer:

Step-by-step explanation:

let the length of rectangle=l units

width=9

p=2(l+9)

area=9l

9l=2(l+9)

9l=2l+18

7l=18

l=18/7 units

5 0
3 years ago
What is the x-coordinate of the point of intersection for the two lines below?
Brut [27]

Answer:

From the graph, it is clear that the point of intersection is:

  • (x, y) = (-4, -1)

And the x-coordinate of the point of intersection for the two lines is:

  • x = -4

Step-by-step explanation:

  • As we know that the solution of the system of equations is the point of intersection. Let us solve it.

Given the system of equations

\begin{bmatrix}2x+y=-9\\ 2x-5y=-3\end{bmatrix}

solving the system of equations

subtracting 2x+y = -9 from 2x-5y = -3

2x-5y=-3

-

\underline{2x+y=-9}

-6y=6

so

\begin{bmatrix}2x+y=-9\\ -6y=6\end{bmatrix}

solving for y

-6y=6

Divide both sides by -6

\frac{-6y}{-6}=\frac{6}{-6}

y=-1

\mathrm{For\:}2x+y=-9\mathrm{\:plug\:in\:}y=-1

2x-1=-9

2x=-8

Divide both sides by 2

\frac{2x}{2}=\frac{-8}{2}

x=-4

Thus, the x-coordinate of the point of intersection for the two lines below will be:

x=-4

Also, the graph is attached.

From the graph, it is clear that the point of intersection is:

  • (x, y) = (-4, -1)

And the x-coordinate of the point of intersection for the two lines is:

  • x = -4

4 0
3 years ago
Identify the class​ width, class​ midpoints, and class boundaries for the given frequency distribution.
Crank

Answer:

a. Class width=4

b.

Class midpoints

46.5

50.5

54.5

58.5

62.5

66.5

70.5

c.

Class boundaries

44.5-48.5

48.5-52.5

52.5-56.5

57.5-60.5

60.5-64.5

64.5-68.5

68.5-72.5

Step-by-step explanation:

There are total 7 classes in the given frequency distribution. By arranging the frequency distribution into the refine form we get,

Class

Interval frequency

45-48 1

49-52 3

53-56 5

57-60 11

61-64 7

65-68 7

69-72 1

a)

Class width is calculated by taking difference of consecutive two upper class limits or two lower class limits.

Class width=49-45=4

b)

The midpoints of each class is calculated by taking average of upper class limit and lower class limit for each class.

M=\frac{lower class limit+upper class limit}{2}

Class

Interval Midpoints

45-48 \frac{45+48}{2}=46.5

49-52 \frac{49+52}{2}=50.5

53-56 \frac{53+56}{2}=54.5

57-60 \frac{57+60}{2}=58.5

61-64 \frac{61+64}{2}=62.5

65-68 \frac{65+68}{2}=66.5

69-72 \frac{69+72}{2}=70.5

c)

Class boundaries are calculated by subtracting 0.5 from the lower class limit and adding 0.5 to the upper class interval.

Class

Interval Class boundary

45-48 44.5-48.5

49-52 48.5-52.5

53-56 52.5-56.5

57-60 56.5-60.5

61-64 60.5-64.5

65-68 64.5-68.5

69-72 68.5-72.5

7 0
3 years ago
DOES SOMEONE KNOW HOW TO DO THIS??????
Natalka [10]

Volume of prism= (Area of the trangle)*lenght

Area of the Triangle= (b*h)/2=7 ft *5 ft /2=35 ft /2=17.5 ft²

lenght is 8 ft

Volume= 17.5 ft² * 8 ft = 140 ft³

5 0
4 years ago
Point A is at (-6,5) and point B is at (3,-7)<br> What is the midpoint of line segment AB?
Oxana [17]

Answer:

( -1.5, -1)

Step-by-step explanation:

add the x values together and divide by 2 and add the y values together and divide by 2

x: -6 + 3 = -3 divided by 2   x = -1 1/2 or -1.5

y: 5 + (-7) = -2 divided by 2  y = -1

3 0
3 years ago
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