Answer:
\frac{x^4+5}{x^3(x^2+6)} =\frac{A}{x}+\frac{B}{x^2}+\frac{D}{x^3} +\frac{Ex+F}{x^2+6}
Step-by-step explanation:
What is the square root of -1? Т - ОООО Т -
2 answers:
You might be interested in
12x-16y= -48
Set x=0
-16y= -48; y= 3
(0, 3)
Set x=0
12x= -48
x= -4
<span> (-4,0) </span>
Set x=0
-16y= -48; y= 3
(0, 3)
Set x=0
12x= -48
x= -4
<span> (-4,0) </span>