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Burka [1]
3 years ago
8

A container contains balls numbered from 1 to 55. A ball is drawn randomly. What is the probability that the first ball is numbe

r 9 and the second ball is number 41?
Mathematics
1 answer:
Nadusha1986 [10]3 years ago
6 0

Answer:

1/55 * 1/55 = 1/3025

Step-by-step explanation:

The probability of 2 consecutive events is:

P(A and B) = P(A) * P(B) - where P(something) is the probability of it

so:

P(picking 9) = 1 possibility out of 55 total, so 1/55

P(picking 41) = 1 possibility out of 55 total, so 1/55

Finally:

P(9 and 41) = 1/55 * 1/55 = 1/3025

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