
Used:

Functions have the same derivatives if they differ a constant.
h(x) = f(x); g(x) = f(x) + const.
h'(x) = f'(x)
g'(x) = (f(x) + const.)' = f'(x) + (const.)' = f'(x) + 0 = f'(x)
h'(x) = g'(x)
Therefore yuor answer is A. f'(x)=g'(x)

Used:

Answer:
B
Step-by-step explanation:
given the 2 equations
y - 4x = 12 → (1)
2 - y = 2(x + 2)² → (2)
rearrange (1) expressing y in terms of x
y = 12 + 4x
Simplify (2) by expanding factor and substituting y = 12 + 4x
2 - (12 + 4x) = 2(x² + 4x + 4)
2 - 12 - 4x = 2x² + 8x + 8
- 10 - 4x = 2x² + 8x + 8 ← rearrange into standard form
add 10 + 4x to both sides
2x² + 12x + 18 = 0 ← in standard form
divide through by 2
x² + 6x + 9 = 0
(x + 3)(x + 3) = 0 ⇒ (x + 3)² = 0 ⇒ x = - 3
Point of intersection = (- 3, 0 ) → B
Answer:
Average rate of change for the function
over the interval -1<x<1 is -1
Step-by-step explanation:
We need to find average rate of change of f over the interval -1 < x < 1
The function given is: 
The formula used to find average rate of change is:

We have, a = -1 and b = 1
Finding f(b) when b=1

Now, finding f(a), when a= -1

Now, putting values and finding average rate of change

So, average rate of change for the function
over the interval -1<x<1 is -1