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3 years ago

9

Meh idc whats up fook whatcha nee

2 answers:

Nostrana [21]3 years ago

7 0

Answer:

alrr

Step-by-step explanation:

ololo11 [35]3 years ago

5 0

Answer: Hi, Welcome to Jollibee how may i help you

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Find m<q plzzzzzzzzzzz

Eva8 [605]

66 is the answer
76+ 38= 114
114+ 66 = 180

4 0

3 years ago

Use the method of ELIMINATION to solve the system. You must SHOW ALL WORK. Make sure you have an answer for both x and y.

jekas [21]

Answer:

<h3>Required <u>Answer</u><u>:</u><u>-</u></h3>

$\sf 4x+8y=10\dots\dots (1)$

$\sf -4x+2y=-30\dots\dots (2)$

by adding eq (1) and eq (2) we get

${:}\longrightarrow$ $\sf 4x+8y=20$

${:}\longrightarrow$ $\sf -4x+2y=-30$

<h2>__________________________</h2>

${:}\longrightarrow$ $\sf 10y=-10$

${:}\longrightarrow$ $\sf y={\dfrac {-10}{10}}$

${:}\longrightarrow$ ${\underline{\boxed{\bf y=-1}}}$

Substitute the value in eq (2)

${:}\longrightarrow$ $\sf -4x+2 (-1)=-30$

${:}\longrightarrow$ $\sf -4x-2=-30$

${:}\longrightarrow$ $\sf -4x=-30+2$

${:}\longrightarrow$ $\sf -4x=-28$

${:}\longrightarrow$ $\sf x={\dfrac {-28}{-4}}$

${:}\longrightarrow$ ${\underline{\boxed{\bf x=7}}}$

$\therefore$ ${\underline{\boxed{\bf (x,y)=(7,-1)}}}$

6 0

3 years ago

Read 2 more answers

Simplify 5 (2 squared) -1^2

Serggg [28]

19 is the answer since 2 to the 2nd power is 4 5×4=20 -1 to the 2nd power is -1
20-1=19

8 0

3 years ago

Read 2 more answers

the seventh and eighth grade bands held a joint concert. together there was 188 band members. if the eight grade band is 3 times

Montano1993 [528]

8th grade = 3x = 3(47) = 141 band members.

7th + 8th = 188

7th = x
8th = 3x

x + 3x = 188 ; x = 47 ; 47 + 3(47) = 47 + 141 = 188
4x = 188
4x / 4 = 188 / 4
x = 47 --> 7th grade

8th grade = 3x = 3(47) = 141

To check:
x + 3x = 188 ; x = 47 ;
47 + 3(47) = 188
47 + 141 = 188
188 = 188

4 0

3 years ago

Read 2 more answers

3. Solve the system using elimination (not substitution or matrices). negative 2 x plus y minus 2 z equals negative 8A N D7 x pl

riadik2000 [5.3K]

Elimination Method

$\begin{gathered} -2X+Y-2Z=-8 \\ 7X+Y+Z=-1 \\ 5X+2Y-Z=-9 \end{gathered}$

If we multiply the equation 3 by (-1) we obtain this:

$\begin{gathered} -2X+Y-2Z=-8 \\ 7X+Y+Z=-1 \\ -5X-2Y+Z=9 \end{gathered}$

If we add them we obtain 0, therefore there are infinite solutions. So, let's write it in terms of Z

1. Using the 3rd equation we can obtain X(Y,Z)

$\begin{gathered} 5X=-9-2Y+Z \\ X=\frac{-9-2Y+Z}{5} \\ \end{gathered}$

2. We can replace this value of X in the 1st and 2nd equations

$\begin{gathered} -2\cdot(\frac{-9-2Y+Z}{5})+Y-2Z=-8 \\ 7\cdot(\frac{-9-2Y+Z}{5})+Y+Z=-1 \end{gathered}$

3. If we simplify:

$\begin{gathered} \frac{-9Y+12Z-63}{5}=-1 \\ \frac{9Y-12Z+18}{5}=-8 \end{gathered}$

4. We can obtain Y from this two equations:

$\begin{gathered} Y=-\frac{-12Z+58}{9} \\ \end{gathered}$

5. Now, we need to obtain X(Z). We can replace Y in X(Y,Z)

$\begin{gathered} X=\frac{-9-2Y+Z}{5} \\ X=\frac{-9-2(-\frac{-12Z+58}{9})+Z}{5} \end{gathered}$

6. If we simplify, we obtain:

$X=\frac{-3Z+7}{9}$

7. In conclusion, we obtain that

(X,Y,Z) =

$(\frac{-3Z+7}{9},-\frac{-12Z+58}{9},Z)$

8 0

1 year ago