Answer:
4600
Step-by-step explanation:
This is an arithmetic sequence with common difference d between consecutive terms.
d = - 2 - (- 6) = 2 - (- 2) = 6 - 2 = 4
The sum to n terms of an arithmetic sequence is
= 
[ 2a + (n - 1)d ]
where a is the first term
here a = - 6, d= 4 and n = 50, hence
= 
[ (2 × - 6) + (49 × 4) ]
= 25 ( - 12 + 196 )
= 25 × 184
= 4600
Answer:
Step-by-step explanation:
It's not c or d. It's not much but I hope it helps.
If George completed 3/5 of work in 9 days, it means that he needs 3 days to finish 1/5th of the work.
The remaining part is 2/5 because 1-3/5=2/5. 2/5 is also 6/15
From this, how much did George do? in the first 3 days he did 1/5th and then one more day was left, during which he did 1/5/3=1/15th.
So he did in total 1/15+1/5=1/15+3/15=4/15.
this means that Paul did the rest of 6/15, so Paul did 6/15-4/15=2/15.
So we know that he does 2/15 in 4 days, which means that every two days he can do 1/15 of the work
so he would need 15 times 2 days to finish the work - 30 days!
Answer:
B. is your answer.
Step-by-step explanation:
Answer: 3t²(2st⁷ - s⁶ - 2t⁵)
<u>Step-by-step explanation:</u>
5s⁶t² + 6st⁹ - 8s⁶t² - 6t⁷ <em>5s⁶t² and - 8s⁶t² are like terms which = -3s⁶t² when combined</em>
= 6st⁹ - 3s⁶t² - 6t⁷ <em>next, factor out the GCF of 3t²</em>
= 3t²(2st⁷ - s⁶ - 2t⁵)
