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ch4aika [34]
4 years ago
14

SOLVE 21-24for me. All multiple choice

Mathematics
1 answer:
Elena L [17]4 years ago
6 0
21) D
22) A
23) B
24) D
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For the first one it equals 2,300,000
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In two or more complete sentences, analyze how to find the third term in the expansion of (2x + y)4.
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<span> The first term in the binomial is "<span>x2</span>", the second term in "3<span>", and the power </span>n<span> is </span>6, so, counting from0<span> to </span>6, the Binomial Theorem gives me:(<span>x2 + 3)6  =  6C0 (x2)6(3)0 + 6C1(x2)5(3)1 + 6C2 (x2)4(3)2 + 6C3 (x2)3(3)3</span><span>+ 6C4 (x2)2(3)4 + 6C5 (x2)1(3)5 + 6C6 (x2)0(3)6</span></span><span>Then simplifying gives me<span><span>(1)(x12)(1) + (6)(x10)(3) + (15)(x8)(9) + (20)(x6)(27)</span><span><span>+ (15)(x4)(81) + (6)(x2)(243) + (1)(1)(729)</span><span>= </span><span>x12<span> + 18</span>x10<span> + 135</span>x8<span> + 540</span>x6<span> + 1215</span>x4<span> + 1458</span>x2<span> + 729</span></span><span><span>
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6 0
3 years ago
Read 2 more answers
Find the balance in the account after the given period.
Lapatulllka [165]

Answer:

balance after 4 years = $4502

Step-by-step explanation:

Formula to get the final amount when compounded annually is,

Final amount = \text{Principal amount}\times (1+\frac{r}{n})^{nt}

Here, r = rate of interest

n = number of compounding per year

t = Duration of investment

From the given question,

Final amount = 4000(1+\frac{0.03}{1})^{(1\times 4)}

                      = 4000(1.03)^4

                      = 4502.0352

                      ≈ $4502

Therefore, balance after 4 years = $4502

8 0
3 years ago
Work out the value of (3^2)2 x (10^3)2
aalyn [17]

Answer:

Value In Scientific Notation Will Be: 3.6 x 10^4

Expanded Form Will Be: 36000

5 0
3 years ago
Part 1. Please show work. Please assist me with these math problems. ​
Vitek1552 [10]

Answer: 1) 2, 3, 4, 9, 32, 279, 8896, 2481705, 22077238784

              2) 2,490,924

              3) Neither

<u>Step-by-step explanation:</u>

S_n=S_{n-2}\cdot (S_{n-1}-1)\quad \\\\S_1=2\quad given\\S_2=3\quad given\\S_3=S_1(S_2-1)\quad =2(3-1)\quad =4\\S_4=S_2(S_3-1)\quad =3(4-1)\quad =9\\S_5=S_3(S_4-1)\quad =4(9-1)\quad =32\\S_6=S_4(S_5-1)\quad =9(32-1)\quad =279\\S_7=S_5(S_6-1)\quad =32(279-1)\quad =8,896\\S_8=S_6(S_7-1)\quad =279(8896-1)\quad =2,481,705\\S_9=S_7(S_8-1)\quad =8896(2481705-1)\quad =22,077,238,784

\sum^8_{k=1}S_k\\\\=S_1+S_2+S_3+S_4+S_5+S_6+S_7+S_8\\\\= 2,490,924\\

Neither

Not arithmetic because the difference between each of the terms is not the same.            

                        S₂ - S₁          S₃ - S₂           S₄ - S₃      

                      3 - 2 = 1       4 - 3 = 1          9 - 4 = 5

Not geometric because the ratios between each of the terms is not the same.                

                       \dfrac{S_2}{S_1}=\dfrac{S_3}{S_2}\qquad \rightarrow \dfrac{3}{2}=\dfrac{4}{3}\qquad \rightarrow \text{cross multiply to get}: 9\neq 8

8 0
3 years ago
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