H1 (t) = 196 - 16 t-squared. / / / H2 (t) = 271-16t-squared. / / / In each function, 't' is the number of seconds after that ball is dropped. / / / Each function is only true until the first time that H=0, that is, until the first bounce. Each function becomes very complicated after that, and we would need more information in order to write it.
Answer:
5.14 km
Step-by-step explanation:
A semicircle is 1/2 of a circle so the perimeter is just 1/2 of the circumference
C = 2 * pi r for a circle so for a semicircle
1/2* 2* pi *r
pi*r
3.14 * 1
3.14
If we want to include the piece that closes the semicircle, we need to add the diameter
d = 2r = 2(1) = 2
2+3.14 = 5.14
The depth of the bottom of the hole after the second day is 36 feet using addition operation.
<h3>What is addition?</h3>
In math, addition is the process of adding two or more integers together. Addends are the numbers that are added, while the sum refers to the outcome of the operation.
Given the depth on the first day is 26 ½ feet.
Depth on the second day = 9½ feet more than on the first day i.e. 9½ feet + depth on the first day
This implies, depth on the second day = 9½ + 26 ½
= 36 feet
Therefore, the depth of the bottom of the hole after the second day is 36 feet.
To learn more about addition, visit:
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Find the minimum, first quartile, median, third quartile, and maximum of each data set, 12, 10, 11, 7, 9, 10, 5
Sliva [168]
To find the median:
Least to greatest order:
5, 7, 9, 10, 10, 11, 12
10 is the number in the middle. Therefore the median is 10