Answer:
11
Step-by-step explanation:
Just count it
You can use variables to solve this problem. Lets say that m is men, w is women, and c is children. m+w+c=266
four times as many men as children in ‘math words’ would be 4c=m
twice as many women as children would be 2c=w
what we can do now is plug those in to make everything easier with one variable
4c+2c+c=266
7c=266
c=38 now we have how many children, and we need to plug it back into what we have for women and men.
4c=m 4(38)=m m=152
2c=w 2(38)=w w=76
152 men, 76 women, and 38 children
Answer:
we need at least 17 - card deck
Step-by-step explanation:
From the information given :
We can attempt to solve the question by using pigeonhole principle;
"The pigeonhole principle posits that if more than n pigeons are placed into n pigeonholes some pigeonhole must contain more than one pigeon"
Thus; the minimum number of pigeon; let say at least n pigeons sit on at least one same hole among m hole can be represented by the formula:
m( n - 1 ) + 1
where ;
pigeons are synonymous to card
pigeonholes are synonymous to suits
So; m = 4 ; n = 5
∴ 4 (5 -1 ) + 1 ⇒ 4 (4) + 1
= 16 + 1
= 17
Hence; we need at least 17 - card deck
