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ivanzaharov [21]

2 years ago

5

The product of two numbers is the same as one of the factors. How can you use properties of multiplication to determine what the

the factors are?

1 answer:

Bess [88]2 years ago

4 0

It will be as I understand:

(x*y)=x
<span>
or (x*y)=y</span>

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3/7 =9/x<br><br><br><br> solve the following proportions ( they are fractions) thanks!

tresset_1 [31]

3/7 = 9/x
cross multiply because thats how u solve proportions
(3)(x) = (7)(9)
3x = 63
x = 63/3
x = 21

and if u will notice : 3/7 and 9/21 ....9/21 reduces to 3/7....so these are equivalent fractions...because proportions are nothing but equivalent fractions

6 0

3 years ago

What is 4 over 49 divided by 2? Please answer as soon as possible!! Thanks so much!!!!

rusak2 [61]

In exact form that would 2 over 49 and in decimal form that would be 0.04.

6 0

3 years ago

Find the value of given expression<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B220%20%2B%20221%7D%20" id="TexFormula1"

Ymorist [56]

Answer:

the answer will be 21 I hope this help you

5 0

3 years ago

Read 2 more answers

Round 96.39 to the tenths place

kykrilka [37]

9 is in the tenths place, since the rule is if a number is more than 5 you add one to it so 9 becomes a 10 and the 3 on its left becomes a 4. so the answer is 96.40 or 96.4

7 0

3 years ago

Here are summary statistics for randomly selected weights of newborn girls: n=185,

Anna11 [10]

Answer:

The confidence interval for the population mean μ is $32.487$

Step-by-step explanation:

Given :

Number of weights of newborn girls n=185.

Mean $\bar{x}=31.4$ hg

Standard deviation s=7.5 hg

Use a 95% confidence level i.e. cl=0.95

To find : What is the confidence interval for the population mean μ?

Solution :

Using t-distribution,

The degree of freedom $DF=n-1=185-1=184$

$\alpha=\frac{1-0.95}{2}$

$\alpha=0.025$

The t critical value is t=1.973.

The confidence interval build is

$CI=\bar{x}\pm(t\cdot \frac{s}{\sqrt{n}})$

Substitute the values,

$CI=31.4\pm(1.973\cdot \frac{7.5}{\sqrt{185}})$

$CI=31.4\pm(1.973\cdot 0.5514)$

$CI=31.4\pm(1.087)$

$31.4+1.087$

$32.487$

Therefore, the confidence interval for the population mean μ is $32.487$

6 0

2 years ago