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svetlana [45]
2 years ago
15

What is the range of the data set 62,35,84,16, 47,21, 35

Mathematics
2 answers:
Rudik [331]2 years ago
6 0
The range is the highest number in the set minus the lowest number in the set so
84-16=
68
Rashid [163]2 years ago
3 0
What is the range of the data set of these numbers ?

The range is the highest number minused by the lowest number

So out of this data set
84-16 is the range to get a range of 68


The range of the data set is 68.

Hope this helps ☺️
(Brainliest if it taught you how to do it)
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Theo has a balence of $-4 in his savings account. After making a deposit, he has $25 in his account.What is the overall change t
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Find the coordinates of the midpoint M of the segment with the given endpoints. Then find the distance between the two points. R
Mrac [35]

Answer:

Midpoint (-2,4)

distance nearest tenth = 8.9

The approximate distance = 9

Step-by-step explanation:

Formulas

PQ midpoint = (x2 + x1)/2, (y2 + y1)/2

distance d = sqrt( (x2 - x1)^2 + (y2 - y1)^2 )

Givens

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The distance = sqrt(16 + 64)

The distance = sqrt(80)

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3 years ago
At the beginning of each of her four years in college, Miranda took out a new Stafford loan. Each loan had a principal of $5,500
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Answer:

D. $31,337.27

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The rate of interest on the loan is 7.5% i.e. 0.075 and it was for the duration of 10 years.

Also, it is given that the loan was compounded annually.

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P=\frac{\frac{r}{n}\times PV}{1-(1+\frac{r}{n})^{-t\times n}}

i.e. PV=\frac{P\times [1-(1+\frac{r}{n})^{-t\times n}]}{\frac{r}{n}}

Substituting the values, we get,

i.e. PV=\frac{P\times [1-(1+\frac{0.075}{12})^{-10\times 12}]}{\frac{0.075}{12}}

i.e. 22000=\frac{P\times [1-(1+0.00625)^{-120}]}{0.00625}

i.e. 22000=\frac{P\times [1-(1.00625)^{-120}]}{0.00625}

i.e. 22000=\frac{P\times [1-0.4735]}{0.00625}

i.e. 22000=\frac{P\times 0.5265}{0.00625}

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Thus, the total lifetime cost to pay of the loans compounded annually  = 261.16 × 120 = $31,339.2

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Answer:

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