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kifflom [539]
3 years ago
9

Suppose a normal distribution has a mean of 62 and a standard deviation of

Mathematics
1 answer:
tankabanditka [31]3 years ago
6 0

Answer:

66.8% or 0.66772

Step-by-step explanation:

0.66772

Given that :

Mean (m) = 62

Standard deviation (s) = 4

probability that a data value is between 57 and 65

P(57 < x < 65)

Using the relation :

(x - m) / s

P(x < 57) :

(57 - 62) / 4 = - 1.25

P(Z < - 1.25) = 0.10565 ( Z probability calculator)

P(x < 65) :

(65 - 62) / 4 = 0.75

P(Z < 0.75) = 0.77337 (Z probability calculator)

P(Z < 0.75) - P(Z < - 1.25)

0.77337 - 0.10565 = 0.66772

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Jason and Jill or two students in mr. White's math class. On the last 5 quizzes Jason scored an 80 90 95 85 and 70. Jill scored
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Jason's scores : 80 90 95 85 70 and

Jill's score : 70 75 90 100 95.

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Now, in order to find the mean absolute deviation, need to find the difference of each score from means.

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|86-75| = 11

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Jill got average quiz score 86 and Jason got 84.

Therefore, Jill got better quiz average.

Also, the mean absolute deviation for Jason scores is less that is 6.8 than 10.8.

Therefore, Jason got more consistent grades.

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