Can u just post the whole question or elaborate further
Given:
The two functions are:


To find:
The value of
.
Solution:
We have,


We know that,


![(h\circ g)(b)=[(5b-9)-1]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28b%29%3D%5B%285b-9%29-1%5D%5E2)
![(h\circ g)(b)=[5b-10]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28b%29%3D%5B5b-10%5D%5E2)
Putting
, we get
![(h\circ g)(-6)=[5(-6)-10]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28-6%29%3D%5B5%28-6%29-10%5D%5E2)
![(h\circ g)(-6)=[-39-10]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28-6%29%3D%5B-39-10%5D%5E2)
![(h\circ g)(-6)=[-49]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28-6%29%3D%5B-49%5D%5E2)

Therefore, the value of
is 2401.
Answer:
Hey there!
a)
10x-1=4x+2
6x-1=2
6x=3
x=1/2 cm.
10x-1=4 cm.
So the width of the rectangle is 10/4, or 2.5 cm.
b)
l=3w
2l+2w=24
2(3w)+2w=24
6w+2w=24
8w=24
w=3
l=9
The are is 27 units squared.
Let me know if this helps :)
Answer:
w-6b+4/6
Step-by-step explanation:
To get the answer you have to first open the bracket which will give you w=6a+6b-4.You then take 6b-4 to the other side to meet w after this divide all by 6 to make a the subject of the formula.