i. Let t be the line tangent at point J. We know that a tangent line at a point on a circle, is perpendicular to the diameter comprising that certain point. So t is perpendicular to JL
let l be the tangent line through L. Then l is perpendicular to JL ii. So t and l are 2 different lines, both perpendicular to line JL.
2 lines perpendicular to a third line, are parallel to each other, so the tangents t and l are parallel to each other.
Remark. Draw a picture to check the
Answer:
Right isosceles triangle
Step-by-step explanation:
In Right isosceles triangle, two angles are acute and equal, while, the third angle is of 90°
Answer: B. 1/5
Step-by-step explanation:
Answer:
Let width = w
length = 4w/3
Area = 432 = length*width = w*4w/3
4w^2/3 = 432
w^2 = 432*3/4 = 324
w = 18
so the width of the cake pan is 18 inches.
Answer:
83.2 cm^2
Step-by-step explanation:
To solve this we're going to find the area of the bigger triangle (the shaded and unshaded parts together) and then the area of the smaller triangle (the unshaded part) and then subtract that from the area of the bigger triangle. We're going to use the equation: Area=1/2 x base x height. So the base of the big triangle is 16, and the height is (10.4+8.6 = 19). Put into the equation this looks like this: Area=1/2 x 16 x 19, so by multiplying we find that the area is 152 cm^2. Next we find the small triangle's area, Area=1/2 x 16 x 8.6, so the area is 68.8. Then to find the area of the shaded part, we subtract the unshaded area (68.8) from the whole area (152), 152-68.8=83.2.
