All categories

2 years ago

Y+1=x :write the equation in slope intercept form to find the slope and the y-intercept

2 answers:

8 0

You have the equation:

Y + 1 = X

You need it in "slope and intercept" form.
Slope and intercept form is:

Y = (slope) X + (intercept)

The equation you have ALMOST looks like the form you need,
but there's something wrong.

What you have is: Y + 1 = X .
What you need is ' Y ' on one side all by itself.

How can you get rid of that " + 1 " that's on the left side with Y ?

Well, you can subtract ' 1 ' from the left side of the equation.
But whatever you do to one side, you must do the same thing
to the other side.
No problem ! Take the original equation:

Y + 1 = X

Subtract ' 1 ' from each side:

Y = X - 1

And there you have what you need.

Remember, "slope and intercept form" is

Y = (slope) X + (intercept) .

and you have

Y = (1) X + (-1)

The slope is 1 .
The intercept is -1 .

You're letting something easy scare you and
grab you by the throat. Don't let it do that.

Nat2105 [25]2 years ago

5 0

We know that y=MX+c
here m=1 and c=-1

You might be interested in

In the figure below, B lies between A and C. Find the location of B so that AB is 1/8 of AC.

MArishka [77]

Answer:

-3

Step-by-step explanation:

first do -22-2= -24

then do 1/8 of -24= -3

6 0

3 years ago

Problem 10: A tank initially contains a solution of 10 pounds of salt in 60 gallons of water. Water with 1/2 pound of salt per g

AysviL [449]

Answer:

The quantity of salt at time t is $m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })$ , where t is measured in minutes.

Step-by-step explanation:

The law of mass conservation for control volume indicates that:

$\dot m_{in} - \dot m_{out} = \left(\frac{dm}{dt} \right)_{CV}$

Where mass flow is the product of salt concentration and water volume flow.

The model of the tank according to the statement is:

$(0.5\,\frac{pd}{gal} )\cdot \left(6\,\frac{gal}{min} \right) - c\cdot \left(6\,\frac{gal}{min} \right) = V\cdot \frac{dc}{dt}$

Where:

$c$ - The salt concentration in the tank, as well at the exit of the tank, measured in $\frac{pd}{gal}$ .

$\frac{dc}{dt}$ - Concentration rate of change in the tank, measured in $\frac{pd}{min}$ .

$V$ - Volume of the tank, measured in gallons.

The following first-order linear non-homogeneous differential equation is found:

$V \cdot \frac{dc}{dt} + 6\cdot c = 3$

$60\cdot \frac{dc}{dt} + 6\cdot c = 3$

$\frac{dc}{dt} + \frac{1}{10}\cdot c = 3$

This equation is solved as follows:

$e^{\frac{t}{10} }\cdot \left(\frac{dc}{dt} +\frac{1}{10} \cdot c \right) = 3 \cdot e^{\frac{t}{10} }$

$\frac{d}{dt}\left(e^{\frac{t}{10}}\cdot c\right) = 3\cdot e^{\frac{t}{10} }$

$e^{\frac{t}{10} }\cdot c = 3 \cdot \int {e^{\frac{t}{10} }} \, dt$

$e^{\frac{t}{10} }\cdot c = 30\cdot e^{\frac{t}{10} } + C$

$c = 30 + C\cdot e^{-\frac{t}{10} }$

The initial concentration in the tank is:

$c_{o} = \frac{10\,pd}{60\,gal}$

$c_{o} = 0.167\,\frac{pd}{gal}$

Now, the integration constant is:

$0.167 = 30 + C$

$C = -29.833$

The solution of the differential equation is:

$c(t) = 30 - 29.833\cdot e^{-\frac{t}{10} }$

Now, the quantity of salt at time t is:

$m_{salt} = V_{tank}\cdot c(t)$

$m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })$

Where t is measured in minutes.

7 0

3 years ago

If C{1,2} and D={4,5,6}, find C×D by tabulation method. i need for exam

Katarina [22]

Answer:

Step-by-step explanation:

C * D = {(x,y): x is an element of C and y is an element of D.}

C * D = { (1,4), (1,5), (1,6), (2,4), (2,5), (2,6) }

4 0

2 years ago

A recipe calls for 1 1/2 cups of flour, 3/4 cup of white sugar, and 1/8 cup of brown sugar.

alina1380 [7]

Okay this isn't the answer but it is how u can get your answer and explain how to justify it. which math will be how u justify it.... So basically your answer is A.... and you will add 1 1/2 + 3/4 + 1/8 =.25 which is your work they want you to show them and that is what I just showed you in a number line. I hope that's correct, but i'm pretty sure it is. Sorry that took so long i am working still on my own work and still stuck on my own lol. I am not the best with math and this kind of stuff though, but again i am almost sure this is correct

8 0

3 years ago

Read 2 more answers

Help me plz thx<br> jkjl;jkl;jkl;jl

Molodets [167]

Answer:

Copper is being reduced

Step-by-step explanation:

Since the charge of the copper ion went down (2+ --> 0), we can say that Copper is being reduced. An atom is reduced when electrons are added.

3 0

3 years ago