What is the slope of the line that passes through 0(-4, 8) and (5, 2)?
1 answer:
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Answer:
a) see graph
b) No
Step-by-step explanation:
The given relation is
{}
The arrow diagram is shown in the attachment.
b) The relation is not a function because -2 alone maps onto two different y-values.
One-to-many relation cannot be a function.
Answer:
1. For quadrilateral ABCD:
AB = AD = 2.7, BC = DC = 3.2, and AC = 3.168
<BAC = <DAC , <ABC = <ADC =
, and <ACB = <ACD =
2. For quadrilateral ABCE:
AB = EC = 2.7, BC = AE = 3.2, and AC = 3.168
<BAC = <ACE , <ABC = <AEC =
, and <ACB = <EAC =
Step-by-step explanation:
Applying the Cosine rule to triangle ABC,
=
+
- 2/AB/ x /BC/ Cos B
= +
- 2 x 2.7 x 3.2 Cos 64.3
= 7.29 + 10.24 - 17.28 x 0.4337
= 17.53 - 7.49434
= 10.03566
AC =
= 3.168
Applying the Sine rule,
=
=
So that:
=
=
Sin A =
=
= 0.9102
⇒ A = 0.9102
=
But sum of angles in a triangle is , so that;
A + B + C =
65.5 + 64.3 + C =
129.8 + C =
C = - 129.8
C =
1. For quadrilateral ABCD:
AB = AD = 2.7, BC = DC = 3.2, and AC = 3.168
<BAC = <DAC , <ABC = <ADC =
, and <ACB = <ACD =
2. For quadrilateral ABCE:
AB = EC = 2.7, BC = AE = 3.2, and AC = 3.168
<BAC = <ACE , <ABC = <AEC =
, and <ACB = <EAC =