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Naya [18.7K]
3 years ago
13

Pls help i don’t get this subject at all

Mathematics
1 answer:
wolverine [178]3 years ago
7 0
1.)T
2.)F
3.)F
4.)F
5.)T
6.)F
7.)T
8.)T
9.)T
10.)T
A function is f(x)=#x(-+)#
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What group of fungi has reproductive cells with flagella so that they can swim?
Neko [114]
I think that would be the Chytridiomycota fungi
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2 years ago
Read 2 more answers
Jen has 1 chocolate bar she is sharing with her friend, Joe. Jen takes 2/3 of Joe’s piece. What’s Joe’s current piece?
lana66690 [7]

Answer:1/3

Step-by-step explanation:

If Jen has 1 chocolate bar means that he has 3/3 whole .If he gives 2/3 then he will be left with 1/3 part of the chocolate bar.

3 0
2 years ago
Find d / dx ( e^in(x)).
Lena [83]

let's first off apply a log rule of cancellation, keeping in mind that, first off is ln(), not in(), and that ln() is just a shortcut to logₑ.


\bf \textit{Logarithm Cancellation Rules}
\\\\
log_a a^x = x\qquad \qquad \stackrel{\stackrel{\textit{we'll use this one}}{\downarrow }}{a^{log_a x}=x}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
e^{ln(x)}\implies e^{log_e(x)}\implies x
\\\\\\
\cfrac{d}{dx}\left[ e^{ln(x)} \right]\implies \cfrac{d}{dx}[x]\implies 1

5 0
3 years ago
Write rational numbers between 0 and 1
rewona [7]

Step-by-step explanation:

Multiply any number with their denominator

0/1×20=0/20

1/1×20= 20/20

Now,

3/20,5/20,6/20,15/20,18/20.....

3 0
2 years ago
A study of homeowners in the 5th congressional district in Maryland found that their annual household incomes are normally distr
tino4ka555 [31]

Answer:

The minimum income level for this target group is of $51,253.6.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of $41,182 and a standard deviation of $11,990

This means that \mu = 41182, \sigma = 11990

Find the minimum income level for this target group.

The 100 - 20 = 80th percentile, which is X when Z has a p-value of 0.8, so X when Z = 0.84.

Z = \frac{X - \mu}{\sigma}

0.84 = \frac{X - 41182}{11990}

X - 41182 = 0.84*11990

X = 51253.6

The minimum income level for this target group is of $51,253.6.

4 0
3 years ago
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