Pls help i don’t get this subject at all

Mathematics

1 answer:

wolverine [178]3 years ago

7 0

1.)T
2.)F
3.)F
4.)F
5.)T
6.)F
7.)T
8.)T
9.)T
10.)T
A function is f(x)=#x(-+)#

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What group of fungi has reproductive cells with flagella so that they can swim?

Neko [114]

I think that would be the Chytridiomycota fungi

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2 years ago

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Jen has 1 chocolate bar she is sharing with her friend, Joe. Jen takes 2/3 of Joe’s piece. What’s Joe’s current piece?

lana66690 [7]

Answer:1/3

Step-by-step explanation:

If Jen has 1 chocolate bar means that he has 3/3 whole .If he gives 2/3 then he will be left with 1/3 part of the chocolate bar.

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2 years ago

Find d / dx ( e^in(x)).

Lena [83]

let's first off apply a log rule of cancellation, keeping in mind that, first off is ln(), not in(), and that ln() is just a shortcut to logₑ.

$\bf \textit{Logarithm Cancellation Rules}
\\\\
log_a a^x = x\qquad \qquad \stackrel{\stackrel{\textit{we'll use this one}}{\downarrow }}{a^{log_a x}=x}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
e^{ln(x)}\implies e^{log_e(x)}\implies x
\\\\\\
\cfrac{d}{dx}\left[ e^{ln(x)} \right]\implies \cfrac{d}{dx}[x]\implies 1$

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3 years ago

Write rational numbers between 0 and 1

rewona [7]

Step-by-step explanation:

Multiply any number with their denominator

0/1×20=0/20

1/1×20= 20/20

Now,

3/20,5/20,6/20,15/20,18/20.....

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2 years ago

A study of homeowners in the 5th congressional district in Maryland found that their annual household incomes are normally distr

tino4ka555 [31]

Answer:

The minimum income level for this target group is of $51,253.6.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of $41,182 and a standard deviation of $11,990

This means that $\mu = 41182, \sigma = 11990$