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Blababa [14]
3 years ago
5

Amel is trying to estimate how many boxes he will need to store his miniature car collection he is 538 cars and 27 cars will fit

nicely into the boxes he wants to buy Parton use the numbers would like to choose the best pair that will estimate the numbers of boxes and mom needs and then write them in the blank spaces heartbeat estimate the number of boxes amel will need​
Mathematics
1 answer:
iogann1982 [59]3 years ago
4 0
I’m not too sure but it’ll be found
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Will Jennifer owe money or get a refund? How much?
katrin [286]

Answer:

owe money 24,000

Step-by-step explanation:

5 0
3 years ago
The length of a rectangle is 3 more yrd than twice the width. The area is 869yrd^2
Otrada [13]

Width=20.108 yrd and Length=43.216 yrd

Step-by-step explanation:

Let width = w

Length =3+2w

Area = 869 yrd^2

We need to find length and width of rectangle.

The formula used is:

Area= length*width

Putting values:

Area= length*width

869= (3+2w)*(w)

869= 3w+2w^2

2w^2+3w-869=0

Using quadratic equation to find value of width w:

w=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

a=2, b=3 and c=-869

w=\frac{-3\pm\sqrt{(3)^2-4(2)(-869)}}{2(2)}

w=\frac{-3\pm\sqrt{6961}}{4}

w=\frac{-3\pm 83.4}{4}

w=\frac{-3+83.4}{4}\,\,and\,\,w=\frac{-3-83.4}{4}

w=20.108\,\,and\,\,w=-21.6

Since width can't be negative so, width w=20.108

Length will be: L=3+2w = 3+2(20.108)=3+40.216=43.216

So, Width=20.108 yrd and Length=43.216 yrd

Keywords: Area of rectangle

Learn more about Area of rectangle at:

  • brainly.com/question/3306327
  • brainly.com/question/6270221
  • brainly.com/question/6564657

#learnwithBrainly

4 0
3 years ago
I need help please it's a math question
juin [17]

Answer:

-5/6 (negative five divided by six. the fifth option)

Step-by-step explanation:

The numerator is the first number. The denominator is the second number. Sign has to be the same and only one negative to make the fraction negative.

4 0
2 years ago
Read 2 more answers
How many solutions does tan^-1 3 have in interval [0, 2 π)
zhuklara [117]
\bf tan^{-1}(3)\iff tan^{-1}\left( \frac{\pm 3}{\pm 1} \right)=\theta
\\\\\\
thus\qquad tan(\theta)=\cfrac{\pm 3}{\pm 1}\cfrac{\leftarrow opposite=y}{\leftarrow adjacent=x}

now, the angle of θ, can only have a "y" value that is positive on, well, y is positive at 1st and 2nd quadrants

and "x" is positive only in 1st and 4th quadrants

now, that angle θ, can only have those two fellows, "y" and "x" to be positive, only in the 1st quadrant, and also both to be negative on the 3rd quadrant.

and that those two fellows, can also be both negative in the 3rd quadrant
3/1 = 3, and -3/-1 = 3

so, the solutions can only be "3", when both "y" and "x" are the same sign, and that only occurs on the 1st and 3rd quadrants
6 0
2 years ago
Work out the area of a rectangle with base, b = 36mm and perimeter, P = 94mm.​
Alenkasestr [34]

Answer:

396

Step-by-step explanation:

A = bw

A = 36w

P = 2w + 2b

94 = 2w + 2(36)

94 = 2w + 72

-72           -72

--------------------

22 = 2w

----    ----

2       2

11 = w

A = 36(11)

A = 396

The area of the rectangle will be 396.

7 0
3 years ago
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