If we reverse the reaction to read Z + Q → X + Y, the +ΔH would be a -ΔH. Does this indicate that heat is given off or absorbed
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The new temperature (T₂) in the lab = 25.09 °C
<h3>Further explanation</h3>Given
V₁=2.15 ml
T₁ = 17 + 273 = 290 K
P = 740.2 mmHg
V₂ = 2.21 ml
Required
The new temperature (T₂)
Solution
Charles's Law
<em>When the gas pressure is kept constant, the gas volume is proportional to the temperature </em>
Input the value :
T₂=(T₁.V₂)/V₁
T₂=(290 K x 2.21 ml)/2.15 ml
T₂=298.09 K = 25.09 °C