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lbvjy [14]
3 years ago
15

which two conditions can limit the usefulness of the kinetic-molecular theory in describing gas behavior

Chemistry
1 answer:
alex41 [277]3 years ago
7 0

Answer:

The two conditions that can limit the usefulness of the kinetic-molecular theory in describing gas behavior are "high pressure" and "low temperatures". At low temperatures or high pressures, real gases deviate significantly from ideal gas behavior.

Explanation:

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4 mol of water is made up of 2.408×10^24 molecules of water.
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What volume of water is needed for 0.196 mol of CdCl2 to prepare a 3.91 M solution? L
Brilliant_brown [7]

0.050 litres of the water will be required to make a 3.91 M solution with 0.196 moles in it.

Explanation:

Data given:

moles of CdCl_{2} = 0.196 Moles

Molarity of the solution = 3.91 M

Volume in litres =?

molarity is calculated by the formula:

molarity = \frac{number of moles}{volume in litres}

putting the values in the above formula and rearranging it for volume:

volume = \frac{number of moles}{molarity}

volume = \frac{0.196}{3.91}

volume = 0.050 litres

0.050 litres of the water will be required to make a 3.91 M solution with 0.196 moles in it.

Molarity is the number of moles present in a given volume of solution which is given in litres. It is the measurement of the concentration of particular solute in a solution.

4 0
3 years ago
How many molecules of water will be produced if 52.6 g of methane are burned?
dem82 [27]
When the balanced reaction equation of methane combustion is:

CH4 + 2O2 →CO2 + 2H2O

so, we can see that each 1 mole of methane combusted will give 2 moles of water as a product.

so first, we need to get the moles of methane =
                                         
                         = mass of methane /molar mass of methane 

                         = 52.6 g / 16.04 g/mol

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when 1 mol of methane produces→ 2 moles of water 

∴ 3.28 moles methane produces →   X moles of water 

∴ moles of water = 3.28 * 2 

                             = 6.56 moles

when each 1 mole of water has 6.02 x 10^23 (Avogadro's number ) individual molecules:

∴number of molecules of water = 6.56 * 6.02 x 10^23

                                                      = 3.9 x 10^24 molecules                                      
8 0
3 years ago
25cm3 of gas at 1 atm has a temperature of 20 degree celsis .
Andreas93 [3]

Answer:

1.28 atm

Explanation:

To solve this problem, you need to use the gas laws, more specifically the Combined Gas Law. It is P1V1/T1 = P2V2/T2. Simply plug your values in. But be careful! Make sure you convert your 20 degree C and 28 deg C to Kelvin, as that it the only temperature scale the Gas Laws work with. Upon plugging in your values, you get approximately 1.28 atm.

6 0
3 years ago
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